Goroutine缓冲信道死锁

Question

在主要的goroutine中，如果我将值发送到超过容量的通道，我就会陷入死锁，但是如果我发送的是不同的goroutine，就不会出现死锁，为什么？

func main() {
    c := make(chan int, 2)
    for i := 0; i < 3; i++ {
        c <- i
    }
}

func main() {
    c := make(chan int, 2)
    go func() {
        for i := 0; i < 3; i++ {
            c <- i
        }
        close(c)
    }()
    time.Sleep(5 * time.Second)
}

Answer 1

func main() {
   c := make(chan int, 2)
   for i := 0; i < 3; i++ {
       // Blocking operation
       c <- i
   }
}

By default >>>sends<<< and receives block(!) until both the sender and receiver are ready

结帐- https://gobyexample.com/channels

您的频道上没有接收者，主接收方被封锁。