如何在文本列表上返回多个匹配？

Question

我现在有一个函数，它产生一个词和它发生在其中的句子。此时，函数只从术语列表中检索第一个匹配项。我希望能够检索所有的匹配，而不仅仅是第一次。

例如，list_of_matches = ["heart attack", "cardiovascular", "hypoxia"]和一个句子将是text_list = ["A heart attack is a result of cardiovascular...", "Chronic intermittent hypoxia is the..."]

理想的产出是：

['heart attack', 'a heart attack is a result of cardiovascular...'],
['cardiovascular', 'a heart attack is a result of cardiovascular...'],
['hypoxia', 'chronic intermittent hypoxia is the...']

# this is the current function
def find_word(list_of_matches, line):
    for words in list_of_matches:
        if any([words in line]):
            return words, line

# returns list of 'term, matched string'
key_vals = [list(find_word(list_of_matches, line.lower())) for line in text_list if 
find_word(list_of_matches, line.lower()) != None]

# output is currently 
['heart attack', 'a heart attack is a result of cardiovascular...'],
['hypoxia', 'chronic intermittent hypoxia is the...']

Answer 1

你会想在这里使用regex。

import re

def find_all_matches(words_to_search, text):
    matches = []
    for word in words_to_search:
        matched_text = re.search(word, text).group()
        matches.append(matched_text)
    return [matches, text]

请注意，这将返回所有匹配的嵌套列表。