餐厅选择程序

Question

我有个编码问题要解决。我做了一半，但我想不出休息的时间。

以下是问题所在：

你有一群朋友来参加你的高中聚会，你想带他们去当地的一家餐馆吃饭。你不知道他们是否有饮食限制，但你的餐厅选择如下:乔的美食汉堡-素食主义者:不，维甘:不，无麸质:不

主街比萨公司-素食:是的，织女星:不，无麸质:是的

街角咖啡厅-素食主义者:是的，维根:是的，无麸质:是的

妈妈的意大利菜-素食主义者:是的，维甘:不，无麸质:不

素食主义者:是的，素食主义者:是的，无麸质:是的，写一个程序，询问你的聚会中是否有素食、素食或无麸质，然后只展示你可以带他们去的餐馆。

下面是程序输出的一个示例：

Is anyone in your party a vegetarian ? yes
Is anyone in your party a vegan ? no
Is anyone in your party gluten-free ? yes
Here are your restaurant choices:
Main Street Pizza Company
Corner Cafe
The Chef's Kitchen

下面是程序输出的另一个示例：

Is anyone in your party a vegetarian ? yes
Is anyone in your party a vegan ? yes
Is anyone in your party gluten-free ? yes
Here are your restaurants choices:
Corner Cafe
The Chef's Kitchen

下面是我到目前为止编写的代码：

# Get the status of a party
vegetarian = input('Is anyone in your party a vegetarian(yes/no)? ')
vegan = input('Is anyone in your party a vegan(yes/no)? ')
gluten_free = input('Is anyone in your party gluten-free(yes/or)? ')

# Assign restaurants based on the status of a party
if vegetarian == 'yes' and vegan == 'yes' and gluten_free == 'yes':
    print("Here are your restaurant choices: \n"
          "Corner Cafe \n"
          "The Chef's Kitchen")
elif vegetarian == 'no' and vegan == 'no' and gluten_free == 'no':
    print("Here are your restaurant choices: \n"
          "Joe's Gourmet Burgers")

这是输出：

Is anyone in your party a vegetarian(yes/no)? yes
Is anyone in your party a vegan(yes/no)? yes
Is anyone in your party gluten-free(yes/or)? yes
Here are your restaurant choices: 
Corner Cafe 
The Chef's Kitchen

Is anyone in your party a vegetarian(yes/no)? no
Is anyone in your party a vegan(yes/no)? no
Is anyone in your party gluten-free(yes/or)? no
Here are your restaurant choices: 
Joe's Gourmet Burgers

我想要的是写一份声明，根据答案随机选择餐馆。

但我能想出办法。

有人能告诉我怎么做吗？

我没有谷歌。我想学习。不是抄袭。提前谢谢你。

Answer 1

preferences = []
d = {"yes": True, "no": False}

# fill up company preferences
preferences.append(d[input("Is anyone in your party a vegetarian(yes/no)? ")])
preferences.append(d[input("Is anyone in your party a vegan(yes/no)? ")])
preferences.append(d[input("Is anyone in your party gluten-free(yes/or)? ")])

restaurants = {  # initialize a dictionary of all restaurants
    "Joe's Gourmet Burgers": [False, False, False],
    "Main Street Pizza Company": [True, False, True],
    "Corner Cafe": [True, True, True],
    "Mama's Fine Italian": [True, False, False],
    "The Chef's Kitchen": [True, True, True]
}
print("Here are your restaurant choices:")
for restaurant, peculiarities in restaurants.items():  # iterate restaurants
    if all(map(lambda x: x[0] == x[1] or not x[1], zip(peculiarities, preferences))):  # if a restaurant is good for company print it
        print(restaurant)

Answer 2

OOP:用属性将餐馆建模为类实例。提供有意义的str()。

按原样输入，循环遍历Restaurant实例列表，并将可能的内容放入列表中。

从列表中随机选择一个：

class Restaurant:
    # allow mostly named params, no positional ones
    def __init__(self, name, *, vegetarian=False, vegan=False, gluten_free=False):
        self.name = name
        self.vegetarian = vegetarian
        self.vegan = vegan
        self.gluten_free = gluten_free

    def __str__(self): 
        s = [ k[0] for k in zip( ["Vegetarian", "Vegan", "Gluten free"], 
            (self.vegetarian, self.vegan, self.gluten_free)) if k[1]]
        return f"{self.name} {'(' if s else ''}{', '.join(s)}{')' if s else ''}"  

使用类的程序：

restaurants = [
    Restaurant("Joe's Gourmet Burgers"),
    Restaurant("Main Street Pizza Company", vegetarian=True),
    Restaurant("Corner Cafe", vegetarian=True, vegan=True, gluten_free=True),
    Restaurant("Mama's Fine Italian", vegetarian=True),
    Restaurant("The Chef's Kitchen",   vegetarian=True, vegan=True, gluten_free=True),
]

vegetarian = input('Is anyone in your party a vegetarian(y=yes)? ').strip().lower()[0] == "y"
vegan = input('Is anyone in your party a vegan(y=yes)? ').strip().lower()[0] == "y"
gluten_free = input('Is anyone in your party gluten-free(y=yes)? ').strip().lower()[0] == "y"
print()
all_r = []
for r in restaurants:
    # vegetarians can eat vegan, meat lovers can eat vegetarian or vegan
    if (not gluten_free or r.gluten_free) and (not vegan or r.vegan) and (not vegetarian or r.vegetarian or r.vegan):
        print(r)
        all_r.append(r) # add to list for random choice
    
import random
print("\nWe decided on: ", random.choice(all_r)) # choose one from list random

输出2次运行：

Is anyone in your party a vegetarian(y=yes)? n
Is anyone in your party a vegan(y=yes)? n
Is anyone in your party gluten-free(y=yes)? n

Joe's Gourmet Burgers
Main Street Pizza Company (Vegetarian)
Corner Cafe (Vegetarian, Vegan, Gluten free)
Mama's Fine Italian (Vegetarian)
The Chef's Kitchen (Vegetarian, Vegan, Gluten free)

We decided on:  Joe's Gourmet Burgers



Is anyone in your party a vegetarian(y=yes)? y
Is anyone in your party a vegan(y=yes)? n
Is anyone in your party gluten-free(y=yes)? y

Corner Cafe (Vegetarian, Vegan, Gluten free)
The Chef's Kitchen (Vegetarian, Vegan, Gluten free)

We decided on:  The Chef's Kitchen (Vegetarian, Vegan, Gluten free)