Python -3使用while循环来判断游戏问题

Question

我是一个新的Python学习者，我创建了一个游戏，随机滚动3个骰子。我想知道如何回到“否则”下的“戏剧”。请查查我的截图

import random
game = False
game1 = False
def roll():
    money = 0
    while game == False :
            money += 1   
            key = input("Please hit 'y' to roll the 3 dicks: ")
            if key == "y":
                 roll1 = random.randint(0,10)
                 roll2 = random.randint(0,10)
                 roll3 = random.randint(0,10)
                 print("Roll 1,2,3 are: ", roll1, roll2, roll3)
            else:
                print("Invalid input, try again")
                return roll()
            if roll1 == roll2 == roll3:
                money +=1
                print("You Win!")
                print("Your award is ", money)
                game == False
            else:
                play = input("Loss, try again? y or n? ")
                if play == "y":
                   money -= 1
                   game == False
                elif play == "n":
                     break
                else:
                   ??????????????????????

滚()

​

Answer 1

您只需将其放在while循环中即可：

else:
   while True: # you can 
      play = input("Loss, try again? y or n? ")
      if play == "y":
         money -= 1
         game == False
      elif play == "n":
         break
      else:
         pass