如何不让调用将%20转换为单词之间的空格

Question

要向Telegram发送消息，我使用以下模板：

import requests

headers = {
    "User-Agent": "Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/91.0.4472.124 Safari/537.36"}

urlphoto = f'http://127.0.0.1:0001/Home/Site%20de%20Trabalho%20-%20Home.html'
botalert = 'xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx'
chatalert = 'yyyyyyyyyyyyyyyy'
urlalert = f"https://api.telegram.org/bot" + botalert + "/sendMessage?text=" + urlphoto + "&chat_id=" + chatalert + "&parse_mode=HTML"
requests.get(urlalert, headers=headers)

但是，当消息被发送时，在那里接收到的链接不会聚集在一起，因为%20被转换成空格：

​

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我应该怎样做才能将链接完美地交付如下：

http://127.0.0.1:0001/Home/Site%20de%20Trabalho%20-%20Home.html

Answer 1

使用参数字典，参数将为您正确编码：

import requests

headers = {
    "User-Agent": "Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/91.0.4472.124 Safari/537.36"}

urlphoto = f'http://127.0.0.1:0001/Home/Site%20de%20Trabalho%20-%20Home.html'
botalert = 'xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx'
chatalert = 'yyyyyyyyyyyyyyyy'
urlalert = f'https://api.telegram.org/bot{botalert}/sendMessage'
params = {'text':urlphoto, 'chat_id':chatalert, 'parse_mode':'HTML'}
requests.get(urlalert, headers=headers, params=params)

Answer 2

您可以像这样定义You照片：

urlphoto = f'http://127.0.0.1:0001/Home/Site%20de%20Trabalho%20-%20Home.html'.replace('%20', '%2520')

这将打印百分之二十之后的签名。

Answer 3

试试这个：

import requests
from requests.utils import quote

headers = {
    "User-Agent": "Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/91.0.4472.124 Safari/537.36"}

urlphoto = 'http://127.0.0.1:0001/Home/Site%20de%20Trabalho%20-%20Home.html'
botalert = 'xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx'
chatalert = 'yyyyyyyyyyyyyyyy'
urlalert = f"https://api.telegram.org/bot{botalert}/sendMessage"
requests.get(urlalert, params=quote(f"?text={urlphoto}&chat_id={chatalert}&parse_mode=HTML"), headers=headers)