如何划分包含0的一组数字？

Question

我试图给一个变量赋值，这些值是通过除以其他两个而得到的，然而，其中一个除以0。

我的变量是以下total_cost=[312198.0,230400.0,374345.0,367979.0,415502.0) alpha=0.8181818181818182,0.6666666666666666,0.3076923076923077,0.6153846153846154,0.0

我想要的输出是有cost_feasibility_efficiency=381575.33,345949.94,1216621.24,597965.87,0

我目前的代码是

cost_feasibility_efficiency=[0.0,0.0,0.0,0.0,0.0]
for i in range(0,len(alpha)):
    cost_feasibility_efficiency[i]=total_cost[i]/alpha[i]
    
print(cost_feasibility_efficiency) 

我得到的错误是“浮子除以零”。

Answer 1

由于不允许将分母alpha[i]除以零，所以我们只需确保分母alpha[i]在除以之前不等于零：

    cost_feasibility_efficiency=[0.0,0.0,0.0,0.0,0.0]
    for i in range(0,len(alpha)):
        if alpha[i] == 0:
            cost_feasibility_efficiency[i] = 0.0
        else:
            cost_feasibility_efficiency[i]=total_cost[i]/alpha[i]

    print(cost_feasibility_efficiency) 

你可以选择如果我们被除以零会发生什么。在上述情况下，它只是将结果设置为0.0。

Answer 2

您可以使用try/except捕获异常：

cost_feasibility_efficiency=[0.0,0.0,0.0,0.0,0.0]
for i in range(0,len(alpha)):
    try:
        cost_feasibility_efficiency[i] = total_cost[i] / alpha[i]
    except ZeroDivisionError:
        cost_feasibility_efficiency[i] = 0.0

print(cost_feasibility_efficiency)