执行删除操作后的列表是：<filter对象在python中出现0x000001D5A0952FA0>错误

Question

# Python 3 code to demonstrate
# to remove elements present in other list
# using filter() + lambda

# initializing list
list1 = [1, 3, 4, 6, 7]

# initializing remove list
list2 = [3, 6]

# printing original list
print("The original list is : " + str(list1))

# printing remove list
print("The original list is : " + str(list2))

# using filter() + lambda to perform task
res = filter(lambda i: i not in list1, list2)

# printing result
print("The list after performing remove operation is : " + str(res))

Output-:
The original list is : [1, 3, 4, 6, 7]
The original list is : [3, 6]
The list after performing remove operation is : <filter object at 0x000001D5A0952FA0>


Expected output-:
The original list is : [1, 3, 4, 6, 7]
The original list is : [3, 6]
The list after performing remove operation is : [1, 4, 7]

这里有什么问题？我为什么要犯这个错误。我真的不能把这件事当回事。我在名为“极客健忘”的网站上找到了这个，并试着运行它。

https://www.geeksforgeeks.org/python-remove-all-values-from-a-list-present-in-other-list/

Answer 1

这两个列表位于错误的位置，要显示结果，可以将筛选器对象转换为列表。

res = list(filter(lambda i: i not in list2, list1))

print("The list after performing remove operation is : " + str(res))

OUTPUTS: The list after performing remove operation is : [1, 4, 7]

Answer 2

您需要更改筛选函数参数。您的代码应该是这样的

list1 = [1, 3, 4, 6, 7]

# initializing remove list
list2 = [3, 6]

# printing original list
print("The original list is : " + str(list1))

# printing remove list
print("The original list is : " + str(list2))

# using filter() + lambda to perform task
res = list(filter(lambda i: i not in list2, list1))

print(list1)
print(list2)
print(res)

此代码的输出将如下所示

The original list is : [1, 3, 4, 6, 7]
The original list is : [3, 6]
[1, 3, 4, 6, 7]
[3, 6]
[1, 4, 7]