Kotlin打印List<Strings>的所有组合

Question

我正试图在科特林打印一个列表的所有组合。

我的脚本有一条带有加密消息的可变消息。我想要的是这个变量的所有组合(在空间上分裂)。我已经在空间上把它分开了，所以它变成了一个字符串列表。

期望输出的示例：

1. Y2MPyYU4kblEXrEfExry4AIRAjqdke+JyQQN50Uj5GuCu5rE66lEzQXB5bE VOlNGRoU06Ny4vh/gzSPFV0mHUrxaaAVt1BwN1WN1HFT7baIejtR5KyG6 JK8yC70CpuPZV610coCiWzdFICcgEtAdQaesScLrg495kxofzG3EGvA=

1. Y2MPyYU4kblEXrEfExry4AIRAjqdke+JyQQN50Uj5GuCu5rE66lEzQXB5bE JK8yC70CpuPZV610coCiWzdFICcgEtAdQaesScLrg495kxofzG3EGvA= VOlNGRoU06Ny4vh/gzSPFV0mHUrxaaAVt1BwN1WN1HFT7baIejtR5KyG6

1. VOlNGRoU06Ny4vh/gzSPFV0mHUrxaaAVt1BwN1WN1HFT7baIejtR5KyG6 JK8yC70CpuPZV610coCiWzdFICcgEtAdQaesScLrg495kxofzG3EGvA= Y2MPyYU4kblEXrEfExry4AIRAjqdke+JyQQN50Uj5GuCu5rE66lEzQXB5bE

等等。

我的代码：

// Input data
var message: String = "Y2MPyYU4kblEXrEfExry4AIRAjqdke+JyQQN50Uj5GuCu5rE66lEzQXB5bE VOlNGRoU06Ny4vh/gzSPFV0mHUrxaaAVt1BwN1WN1HFT7baIejtR5KyG6 JK8yC70CpuPZV610coCiWzdFICcgEtAdQaesScLrg495kxofzG3EGvA="

// Info Message
var messageLength = message.length
println("Message = $message\n")

// Info parts
var messageSplitOnSpace = message.split(" ")
for (part in messageSplitOnSpace) {
    var partLength = part.length
    println("Part = $part\n")
}

// Print all combinations 
var mixSize: Int = messageSplitOnSpace.size*messageSplitOnSpace.size;
for (part in messageSplitOnSpace) {

}

输出：

Y2MPyYU4kblEXrEfExry4AIRAjqdke+JyQQN50Uj5GuCu5rE66lEzQXB5bE VOlNGRoU06Ny4vh/gzSPFV0mHUrxaaAVt1BwN1WN1HFT7baIejtR5KyG6 JK8yC70CpuPZV610coCiWzdFICcgEtAdQaesScLrg495kxofzG3EGvA=消息=

消息

Part = Y2MPyYU4kblEXrEfExry4AIRAjqdke+JyQQN50Uj5GuCu5rE66lEzQXB5bE

Part = VOlNGRoU06Ny4vh/gzSPFV0mHUrxaaAVt1BwN1WN1HFT7baIejtR5KyG6

Part = JK8yC70CpuPZV610coCiWzdFICcgEtAdQaesScLrg495kxofzG3EGvA=

Answer 1

var message: String = "Y2MPyYU4kblEXrEfExry4AIRAjqdke+JyQQN50Uj5GuCu5rE66lEzQXB5bE VOlNGRoU06Ny4vh/gzSPFV0mHUrxaaAVt1BwN1WN1HFT7baIejtR5KyG6 JK8yC70CpuPZV610coCiWzdFICcgEtAdQaesScLrg495kxofzG3EGvA="

var items = message.split(" ")

val result = items
  .flatMap { i1 ->
    items.flatMap { i2 ->
      items.mapNotNull { i3 ->
        val combination = listOf(i1, i2, i3).distinct()
        if (combination.count() == 3) combination else null
      }
    }
  }
  .mapIndexed { index, it -> "" + (index + 1) + ". " + it[0] + "\n   " + it[1] + "\n   " + it[2] }

for (item in result) {
  println(item + "\n")
}