我需要实现一个调度字典

Question

我需要实现一个分派字典类型并打印出来，我现在有一个打印问题，，我需要打印David 1条目，但是我得到了一个例外，我如何打印它--这个函数有问题printRecord()

def make_medical_Record(name,num):
    medical_Record = {}

    def inData(act):
        if act in medical_Record:
            return True
        return False

    def addData(time,act):
        if act in medical_Record:
            medical_Record[act].append(time)
            medical_Record[act].sort()
        else:
            medical_Record[act] = [time]

    def view(value):
        print(medical_Record.get(value)) if medical_Record.get(value) else print("no events")
   
    def printRecord():
        def hasMore():
            return
        def next():
            return

        print(min(min(medical_Record,key=medical_Record.get())))
    
    instance = {'inData': inData,'notInData': notInData,'addData': addData,'view':view,'printRecord':printRecord }
    return instance

mr=make_medical_Record('David',1)
print(mr)
mr['addData']('15:00','hospital discharge')
pr=mr['printRecord']()

Answer 1

您的printRecord函数看起来无效：

    def printRecord():
        def hasMore():
            return
        def next():
            return

        print(min(min(medical_Record,key=medical_Record.get())))

很难从这段代码中确切地看出它应该做什么，但是您可以使用它作为一个起点来打印记录对象中的所有数据：

    def printRecord():
        print(name, num, medical_Record)