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社区首页 >问答首页 >Tensorflow姿态估计奇异行为

Tensorflow姿态估计奇异行为
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Stack Overflow用户
提问于 2021-12-07 12:03:46
回答 1查看 112关注 0票数 0

我正试图从照片中检测身体部位/地标,但我正面临一个问题。由于某种原因,即使照片中没有膝盖,它也会打印膝盖点。

有什么办法,为什么要解决这个问题吗?或者什么是更好/更快的方法来检测身体点。谢谢

这是我的密码:

代码语言:javascript
复制
import tensorflow as tf
import numpy as np 
import cv2

image_path = "test3.jpg"
image = tf.io.read_file(image_path)
image = tf.image.decode_jpeg(image)

input_image = tf.expand_dims(image, axis=0)
input_image = tf.image.resize_with_pad(input_image, 192, 192)

model_path = "movenet_lightning_fp16.tflite"
interpreter = tf.lite.Interpreter(model_path)
interpreter.allocate_tensors()

input_image = tf.cast(input_image, dtype=tf.uint8)
input_details = interpreter.get_input_details()
output_details = interpreter.get_output_details()
interpreter.set_tensor(input_details[0]['index'], input_image.numpy())
interpreter.invoke()
keypoints = interpreter.get_tensor(output_details[0]['index'])

width = 640
height = 640

KEYPOINT_EDGES = [(0, 1), (0, 2), (1, 3), (2, 4), (0, 5), (0, 6), (5, 7),
    (7, 9), (6, 8), (8, 10), (5, 6), (5, 11), (6, 12), (11, 12), (11, 13),
    (13, 15), (12, 14), (14, 16)]

input_image = tf.expand_dims(image, axis=0)
input_image = tf.image.resize_with_pad(input_image, width, height)
input_image = tf.cast(input_image, dtype=tf.uint8)

image_np = np.squeeze(input_image.numpy(), axis=0)
image_np = cv2.resize(image_np, (width, height))
image_np = cv2.cvtColor(image_np, cv2.COLOR_RGB2BGR)

for keypoint in keypoints[0][0]:
    x = int(keypoint[1] * width)
    y = int(keypoint[0] * height)

    cv2.circle(image_np, (x, y), 4, (0, 0, 255), -1)

for edge in KEYPOINT_EDGES:
    
    x1 = int(keypoints[0][0][edge[0]][1] * width)
    y1 = int(keypoints[0][0][edge[0]][0] * height)

    x2 = int(keypoints[0][0][edge[1]][1] * width)
    y2 = int(keypoints[0][0][edge[1]][0] * height)

    cv2.line(image_np, (x1, y1), (x2, y2), (0, 255, 0), 2)
print(keypoints)
cv2.imshow("pose estimation", image_np)
cv2.waitKey()

这是打印的17点.

代码语言:javascript
复制
[[[[0.14580254 0.44932607 0.49171054]
[0.12085933 0.48325056 0.76345515]
[0.12439865 0.4332864  0.6319262 ]
[0.14748134 0.54644144 0.69355035]
[0.1498755  0.4215817  0.47992003]
[0.36506626 0.63139945 0.85730654]
[0.34724534 0.3317352  0.7910126 ]
[0.61043286 0.6646681  0.76448154]
[0.5989852  0.29230848 0.8800807 ]
[0.8311419  0.7306837  0.7297675 ]
[0.8425422  0.26081967 0.63438255]
[0.85355556 0.5752684  0.79087543]
[0.8471971  0.37801507 0.79199016]
[0.9836348  0.5910964  0.00867963]
[1.0096381  0.33657807 0.01041293]
[0.86401206 0.7281677  0.03190452]
[0.8798219  0.265369   0.01451936]]]]
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回答 1

Stack Overflow用户

回答已采纳

发布于 2021-12-07 12:24:39

姿态模型总是输出所有他们应该检测到的点。如果图片中没有膝盖,模型估计了图像中膝盖的近似点,并给出了输出点,但该点的置信度得分很低。所以你可以通过信心得分来过滤分数。您可以添加一个变量作为信任的阈值,并使用它来筛选点。我在下面的代码中称它为conf_thrs

代码语言:javascript
复制
conf_thrs = 0.5

for keypoint in keypoints[0][0]:
    if keypoint[2] > conf_thrs:
        # if confidence score is more than 0.5 do the following.
        x = int(keypoint[1] * width)
        y = int(keypoint[0] * height)

        cv2.circle(image_np, (x, y), 4, (0, 0, 255), -1)

并通过KEYPOINT_EDGES对循环执行相同的操作。

票数 1
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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/70259807

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