MATLAB中的MSE与SNR，矩阵7*1

Question

n=50;
x=2;
snr = -5:5:25;
zi = zeros(7,50);
mu = 1;
for i=1:length(snr)
    sigma(1,i) =  sqrt(1/(10^(snr(1,i)/10)));
    %Let wi be gaussian ditribution with mean mu= 1 and sigma found above
    wi = normrnd(mu,sigma(1,i),[1,n]);
    zi(i,:) = x + wi;
end

我使用上面的代码找到了zi，但是矩阵是7* 50。我假设这个问题的答案应该是7*1矩阵。有谁能帮帮我吗？谢谢

Answer 1

function check3
clc
n=1;
    x=2;
    snr = -5:5:25;
    zi = zeros(7,1);
    mu = 1;
    for i=1:length(snr)
        sigma(1,i) =  sqrt(1/(10^(snr(1,i)/10)));             
        wi = normrnd(mu,sigma(1,i),[1,n]);
        zi(i,:) = x + wi;
    end
    zi

说明

在原始代码中，我简单地将50替换为1。谢谢。