XML -使用XSLT合并同一节点多次出现的子元素

Question

我有以下由外部系统发送的源文件。

<?xml version="1.0" encoding="utf-8"?>
<root>
  <remoteId>id-sent-by-sender</remoteId>
  <payments>
    <payment>
      <amount>383700</amount>
      <remoteId>unique-id-1</remoteId>
      <beneficiary>
        <accountNumber>CustomerAccount_1</accountNumber>
        <country>fr</country>
        <routingNumber>AAABBBBCCC</routingNumber>
        <title>Dale's Shop</title>
        <email>dale@shop.com</email>
      </beneficiary>
      <feeBearer>
        <party>supplier</party>
        <supplierFeePercent>1.00</supplierFeePercent>
      </feeBearer>
      <currency>eur</currency>
      <dateDue>2021-07-21</dateDue>
      <metaData>
        <data>
          <key>a-key</key>
          <value>a value</value>
        </data>
        <data>
          <key>another-key</key>
          <value>another value</value>
        </data>
      </metaData>
      <reference>
        <row>invoice row 1</row>
      </reference>
      <reference>
        <row>invoice row 2</row>
      </reference>
      <reference>
        <row>invoice row 3</row>
      </reference>
    </payment>
    <payment>
      <amount>100000</amount>
      <remoteId>unique-id-2</remoteId>
      <beneficiary>
        <accountNumber>CustomerAccount_2</accountNumber>
        <country>gb</country>
        <routingNumber>BBBKKKKSSS</routingNumber>
        <title>Ramos Tacos</title>
      </beneficiary>
      <feeBearer>
        <party>supplier</party>
        <supplierFeePercent>1.00</supplierFeePercent>
      </feeBearer>
      <currency>eur</currency>
      <reference>
        <row>invoice row 1</row>
      </reference>
      <reference>
        <row>invoice row 2</row>
      </reference>
      <reference>
        <row>invoice row 3</row>
      </reference>
    </payment>
  </payments>
</root>

我需要将该文件更改为类似下面的内容。

<?xml version="1.0" encoding="utf-8"?>
<root>
  <remoteId>id-send-by-sender</remoteId>
  <payments>
    <payment>
      <amount>383700</amount>
      <remoteId>unique-id-1</remoteId>
      <beneficiary>
        <accountNumber>CustomerAccount_1</accountNumber>
        <country>fr</country>
        <routingNumber>AAABBBBCCC</routingNumber>
        <title>Dale's Shop</title>
        <email>dale@shop.com</email>
      </beneficiary>
      <feeBearer>
        <party>supplier</party>
        <supplierFeePercent>1.00</supplierFeePercent>
      </feeBearer>
      <currency>eur</currency>
      <dateDue>2021-07-21</dateDue>
      <metaData>
        <data>
          <key>a-key</key>
          <value>a value</value>
        </data>
        <data>
          <key>another-key</key>
          <value>another value</value>
        </data>
      </metaData>
      <reference>
        <row>invoice row 1</row>
        <row>invoice row 2</row>
        <row>invoice row 3</row>
      </reference>
    </payment>
    <payment>
      <amount>100000</amount>
      <beneficiary>
        <accountNumber>CustomerAccount_2</accountNumber>
        <country>gb</country>
        <routingNumber>BBBKKKKSSS</routingNumber>
        <title>Ramos Tacos</title>
      </beneficiary>
      <feeBearer>
        <party>supplier</party>
        <supplierFeePercent>1.00</supplierFeePercent>
      </feeBearer>
      <currency>eur</currency>
      <reference>
        <row>invoice row 1</row>
        <row>invoice row 2</row>
        <row>invoice row 3</row>
      </reference>
      <remoteId>unique-id-2</remoteId>
    </payment>
  </payments>
</root>

简而言之，这两个XML之间的区别在于，第一个XML有多个元素<reference>，我需要将这些元素合并到一个出现项中，同时保持所有这些出现项的子元素不变。

使用XSLT可以做到这一点吗？如果是的话，有没有人可以帮忙呢？我在这方面是个新手，虽然我搜索了所有的帖子，但我不知道该怎么去做。

谢谢

Answer 1

我希望看到一个包含标准身份模板和规则的样式表：

<xsl:template match="payment">
  <xsl:copy>
    <xsl:apply-templates/>
    <reference>
      <xsl:copy-of select="reference/row"/>
    </reference>
  </xsl:copy>
</xsl:template>

<xsl:template match="reference"/>