按下arduino后禁用按钮30秒

Question

我正在与Arduino一起工作，因为我是新来的，需要您的帮助，谢谢！我正在打开LED灯通过按钮30秒，所有工作正常，但有一个问题后，按下按钮灯启动从0秒，但如果我按下按钮15秒后，它将从0秒重新开始，那么，有没有任何方法，我可以禁用按钮也30秒，所以它将只运行30秒，即使我会按下按钮，按钮将工作时，只有在30秒后的灯。

    int BUTTON = 2;
    int BUTTONstate = 0;
    int LED = 8;

    void setup() {
    pinMode(BUTTON, INPUT);
    pinMode(LED, OUTPUT); 
    }


    void loop() {
    static unsigned long startTime = 0;

    BUTTONstate = digitalRead(BUTTON);
    if (BUTTONstate == HIGH){
    if (millis() - startTime >= 30000)
    digitalWrite(LED, LOW);        
    }

    else{
    digitalWrite(LED, HIGH);
    startTime = millis();
    }
    }

Answer 1

我让正确的代码工作得很好：

    int pin1 = 13;
    int LED = 8;
    void setup()
    {
      pinMode(pin1, INPUT_PULLUP);
      pinMode(LED, OUTPUT);
    }

    long offAt = 0;
    void loop()
    {
      if ((digitalRead(LED) == LOW ) && (digitalRead(pin1) == LOW) ) //if LED is off  and button is pressed [low because it has pullup resistor]
      { 
        digitalWrite(LED, HIGH);
        offAt = millis() + 30000; //store var of now + 5 seconds
      }

      if (digitalRead(LED) == HIGH) //if led is on
      {
        if (millis() >= offAt) //see if it's time to turn off LED
        {
          digitalWrite(LED, LOW); //it's time. this also re-enables the button
        }
      }
    }