使用循环将十进制转换为二进制

Question

我想写一个程序，把十进制数0到9转换成二进制。我可以编写代码如何使用重复除法将十进制数转换为二进制数。但是，我在创建一个循环时遇到了麻烦，该循环将以二进制格式输出十进制数0到9。

以下是我的代码

number = 0

remainder = 0
x = ""
while number (0,9):
    remainder = (number%2)
    x = str(remainder) + x
    number = number//2
   
    (x[::-1])
    print(number, "is the binary of",x)

Answer 1

以下是您的代码的修复：

number = 123
remainder = 0
x = ""
n = number # don't work on the original number
           # you need it for the final print
while n > 0:  # wrong syntax for the condition
    remainder = (n%2)
    x = str(remainder) + x
    n = n//2
    #(x[::-1])  # this is useless
print(x, "is the binary of", number) # wrong order to print

注意：您还应该利用divmod__，而不是两个单独的%和//操作

Answer 2

以下是您可以执行的操作：

number = 5
n = number
x = ""
while n:
    x = str(n % 2) + x
    n //= 2
    
print("Decimal:", number)
print("Binary:", x)

输出：

Decimal: 5
Binary: 101