304在create-react-app中使用Netlify函数时出错

Question

※在发布问题后编辑了一些代码。下面是新代码。

我正在尝试使用Netlify函数来隐藏我的API密钥来获取数据。但是，它返回一个304，并且似乎不起作用。下面的代码返回错误"SyntaxError: Unexpected < in JSON at position 0“，响应代码为304。

有人能帮我改进一下吗？

函数/fetch-weather.js

const handler = async (event) => {
  try {
    const { city } = event.queryStringParameters;
    const API = process.env.REACT_APP_API_KEY;

    const response = await fetch(
      `https://api.openweathermap.org/data/2.5/weather?q=${city}&appid=${API}`
    );

    const data = await response.json();
    
    return {
      statusCode: 200,
      body: JSON.stringify(data),
    };
  } catch (error) {
    console.log({ statusCode: 500, body: error.toString() });
    return { statusCode: 500, body: error.toString() };
  }
};

module.exports = { handler };

GetCurrentWeather.js

export const getCurrentWeather = async (
  city,
  setLocation,
  setWeather,
  setNotification
) => {
  const fetchWeather = async () => {
    setNotification({ status: 'pending', message: 'Loading...' });

    const response = await fetch(
      `/.netlify/functions/fetch-weather?city=${city}`
    );

    if (!response.ok) {
      throw new Error('cannot get current weather data');
    }

    const data = await response.json();
    return data;
  };

  try {
    const data = await fetchWeather();
    console.log(data);
    setLocation(data.name);
    const [array] = data.weather;
    setWeather(array.main, array.description);
    setNotification({ status: 'success', message: 'Success' });
  } catch (error) {
    console.log(error);
    setNotification({ status: 'error', message: 'Cannot find result' });
  }
};

Netlify.toml

[build]
    functions = "functions"
    publish = "src"

Package.json(运行"npm i netlify-cli --save-dev")

"devDependencies": {
    "netlify-cli": "^6.8.12"
  }

控制台镜像(在打开带有"netlify dev“的页面后) error network

Answer 1

在您的netlify函数中，发出请求后，您需要使用.json来获取json数据

const response = await fetch(
      `https://api.openweathermap.org/data/2.5/weather?q=${city}&appid=${API}`
    );

const data = await response.json();