JS节假日检查

Question

我有一个呼叫中心，我使用这个JS代码让消息在营业时间和营业时间/周末之后进来，它会显示一条消息，说是在支持时间之外，我的问题是，我如何让这个代码在节假日也能工作？

exports.handler = async function(context, event, callback) {
  const moment = require('moment-timezone');
  var now = moment().tz('America/New_York');
  console.log('Current time-->'+now);
  console.log('current hours-->'+now.hour());
  
  let isWorkingHours = false;
  //let isWorkingHours = true; // testing
 
  const weekday = now.isoWeekday(); 
  console.log('weekday-->'+weekday);
  
  if (now.hour() >= 9 && now.hour() <= 17 && weekday <= 5) {
  //if (now.hour() >= 4 && now.hour() <= 20 && weekday <= 2) { // testing
      isWorkingHours = true;
      //Console.log('This is outside working hours');
    }
    callback(null, {
    isWorkingHours: isWorkingHours
    });
}

Answer 1

我在StackOverflow上从别人的帖子中得到了这个假日检查器(我应该记录这个链接，但我忘了)。您可以遍历您感兴趣的所有日期，以创建完整的假日列表，或者只检查给定的日期是否为假日

function check_holiday (dt_date) {

    // check simple dates (month/date - no leading zeroes)
    var n_date = dt_date.getDate(),
        n_month = dt_date.getMonth() + 1;
    var s_date1 = n_month + '/' + n_date;
    
    if (   s_date1 == '1/1'   // New Year's Day
        || s_date1 == '6/14'  // Flag Day
        || s_date1 == '7/4'   // Independence Day
        || s_date1 == '11/11' // Veterans Day
        || s_date1 == '12/25' // Christmas Day
    ) return true;
    
    // weekday from beginning of the month (month/num/day)
    var n_wday = dt_date.getDay(),
        n_wnum = Math.floor((n_date - 1) / 7) + 1;
    var s_date2 = n_month + '/' + n_wnum + '/' + n_wday;
    
    if (   s_date2 == '1/3/1'  // Birthday of Martin Luther King, third Monday in January
        || s_date2 == '2/3/1'  // Washington's Birthday, third Monday in February
        || s_date2 == '5/3/6'  // Armed Forces Day, third Saturday in May
        || s_date2 == '9/1/1'  // Labor Day, first Monday in September
        || s_date2 == '10/2/1' // Columbus Day, second Monday in October
        || s_date2 == '11/4/4' // Thanksgiving Day, fourth Thursday in November
    ) return true;

    // weekday number from end of the month (month/num/day)
    var dt_temp = new Date (dt_date);
    dt_temp.setDate(1);
    dt_temp.setMonth(dt_temp.getMonth() + 1);
    dt_temp.setDate(dt_temp.getDate() - 1);
    n_wnum = Math.floor((dt_temp.getDate() - n_date - 1) / 7) + 1;
    var s_date3 = n_month + '/' + n_wnum + '/' + n_wday;
    
    if (   s_date3 == '5/1/1'  // Memorial Day, last Monday in May
    ) return true;

    // misc complex dates
    if (s_date1 == '1/20' && (((dt_date.getFullYear() - 1937) % 4) == 0) 
    // Inauguration Day, January 20th every four years, starting in 1937. 
    ) return true;
        
    if (n_month == 11 && n_date >= 2 && n_date < 9 && n_wday == 2
    // Election Day, Tuesday on or after November 2. 
    ) return true;
    
    return false;
}

Answer 2

检查特定时间是否在我们的工作范围之外的逻辑在您的if语句中。

我会根据节假日或休息日的时间范围，将其抽象到某种存储中。您可以有一个表或缓存来存储这些假日(您应该提前加载它们)。

这样，您可以执行以下操作：

1. 搜索如果存在日期与当前日期匹配的假日(仅匹配日期而不匹配时间戳，您可以仅按日期使用moment的isSame检查)
2. 如果匹配，则返回isWorkingHours as false

要检查日期是否匹配，您可以使用下面的命令(无论当前时间如何，当您在日期级别进行比较时，它将返回true )：

console.log(moment('2021-05-10 14:00:00').isSame('2021-05-10', 'day'));

Answer 3

以下是你可能想要检查的东西列表：

复活节“

• Weekends
• "Static : Christmas)
• "Variable date”假日(如:复活节)
• Times(如:你的办公室8:00开门)

/* Function that checks if office is available at a specific date
 * @returns {boolean}
 */
function is_office_available (date = new Date()) {

  // weekends, or actually any other day of the week
  let day = date.getDay();
  if ( [0 /*sunday*/, 6 /*saturday*/].includes(day) ) return false;

  // "static date" holidays (formatted as 'DD/MM')
  let dd_mm = date.getDate() + '/' + (date.getMonth()+1);
  if ( ['24/12', '25/12'].includes(dd_mm) ) return false;

  // TODO: "variable date" holidays

  // specific times
  // this logic has to be extended a LOT if, for example, you have
  // the office open from 8:30 to 17:30 with a launch break from 12:00 to 13:00 on weekdays
  // and from 9:00 to 12:00 only on mondays
  let hh = date.getHours();
  if (9 < hh || hh > 17) return false;
  

  // if no test returned true then the office is going to be available on that date
  return true;

}

您可以简单地在if语句中调用此函数。

“可变日期”假期有一个相当长的(和无聊的)实现，这取决于您在国家办事处的假期。