根据值js过滤对象的对象

Question

我有这个对象的对象，我正在尝试获取包含社会对象的项

​

const events = {
    'event-1': { id: 'event-1', channel: 'facebook'},
    'event-2': { id: 'event-2', channel: 'twitter'},
    'event-3': { id: 'event-3', channel: 'slack'},
  };

​

例如，我需要获取具有facebook的事件，并松弛任何想法如何在对象而不是数组的javascript上工作？

谢谢

Answer 1

您可以将其转换为条目，对其进行过滤，然后将其转换回对象：

​

const events = {
    'event-1': { id: 'event-1', channel: 'facebook'},
    'event-2': { id: 'event-2', channel: 'twitter'},
    'event-3': { id: 'event-3', channel: 'slack'},
  }
  
const result = Object.fromEntries( 
    Object.entries(events).filter( ([key,value]) => value.channel == "facebook" || value.channel == "slack")
);

console.log(result);

​

您可以通过将通道放入数组并使用includes来检查通道列表

​

const events = {
    'event-1': { id: 'event-1', channel: 'facebook'},
    'event-2': { id: 'event-2', channel: 'twitter'},
    'event-3': { id: 'event-3', channel: 'slack'},
  }
  
const channels = ["facebook","slack"];
const result = Object.fromEntries( 
    Object.entries(events).filter( ([key,value]) => channels.includes(value.channel))
);

console.log(result);

​

Answer 2

试试这个：

​

const events = {
            'event-1': { id: 'event-1', channel: 'facebook' },
            'event-2': { id: 'event-2', channel: 'twitter' },
            'event-3': { id: 'event-3', channel: 'slack' },
        };
        
var val = Object.values(events).filter(t=>t.channel == 'facebook' || t.channel == 'slack');

console.log(val);

​

Answer 3

维护一个单独的变量，保存所有社交平台，并基于此过滤事件数组……

const socialPlatforms = [
  'facebook',
  'slack'
];

const events = {
  'event-1': { id: 'event-1', channel: 'facebook'},
  'event-2': { id: 'event-2', channel: 'twitter'},
  'event-3': { id: 'event-3', channel: 'slack'},
};

const socialEvents = Object.values(events)
  .filter(event => socialPlatforms.includes(event.channel))
  .map(event => event.id);

console.log(socialEvents);

/*

[ 'event-1', 'event-3' ]

*/