如何在Laravel 5.8中输入相同标题时创建唯一的slug

Question

我想为同一标题创建唯一的弹头。

示例- www.xcv.com/ght-ghy/

示例1- www.xcv.com/ght-ghy-1/

下面是我的控制器代码：

public function addPostDetails(Request $request) {
    $postTitle = $request->postTitle;
    $postDesc = $request->postDesc;
    $postCat = $request->postCat;
    $postTags = $request->tagid; 
    $tags = explode(",", $postTags);
    $postglobid = date('y') . date('s') . $postCat . rand(0000, 9999);
    $posturl = Str::slug($postTitle, '-');
    $galImg = array();
    $postimgnm = NULL;

    if($postimg = $request->hasFile('postWallImage')) {
        $postimg = $request->file('postWallImage');
        $postimgnm = $postimg->getClientOriginalName();
        $storeTo = public_path() . '/images/' . $postglobid;
        File::makeDirectory($storeTo, $mode = 0777, true, true);
        $postimg->move($storeTo, $postimgnm);
    }
    
    if($postimges = $request->hasFile('postImgGal')) {
        $postimges = $request->file('postImgGal');
        foreach($postimges as $imgs) {
            $postimgnms = $imgs->getClientOriginalName();
            $storeTo = public_path() . '/images/' . $postglobid . '/gallery/';
            File::makeDirectory($storeTo, $mode = 0777, true, true);
            $imgs->move($storeTo, $postimgnms);
            array_push($galImg, $postimgnms);
        }
    }
    
    $savecat = $this->savePostByCategory($postCat, $postglobid, 'createcat');
    $savetag = $this->savePostByTag($tags, $postglobid, 'createtag');

    $savepost = new Post;
    $savepost->post_global_id = $postglobid;
    $savepost->post_title = $postTitle;
    $savepost->post_desc = $postDesc;
    $savepost->post_img = $postimgnm;
    $savepost->post_img_gal = json_encode($galImg);
    $savepost->post_url = $posturl;

    $savepost->save();

    return redirect('/seo/viewallpost')->with('postSuccess', 'Blog has been Posted Successfully');
}

Answer 1

您可以使用cviebrock/eloquent-sluggable库来实现此目的

https://github.com/cviebrock/eloquent-sluggable

鼻塞也往往是独一无二的。因此，如果你用相同的标题写另一篇文章，你会想要以某种方式区分它们，通常是在slug的末尾添加一个递增计数器：

http://example.com/post/my-dinner-with-andre-francois

http://example.com/post/my-dinner-with-andre-francois-1

http://example.com/post/my-dinner-with-andre-francois-2

$post = Post::create([
    'title' => 'My Awesome Blog Post',
]);
// $post->slug is "my-awesome-blog-post"

$newPost = $post->replicate();
// $newPost->slug is "my-awesome-blog-post-1"

要实现这一点，只需更新模型

您的模型应该使用Sluggable trait，它有一个您需要定义的抽象方法sluggable()。

use Cviebrock\EloquentSluggable\Sluggable;

class Post extends Model
{
    use Sluggable;

    /**
     * Return the sluggable configuration array for this model.
     *
     * @return array
     */
    public function sluggable(): array
    {
        return [
            'slug' => [
                'source' => 'title'
            ]
        ];
    }
}

Answer 2

尝试将记录的id附加到新的slug中。我相信记录id是唯一的。