错误CS0029:无法将类型‘char[]’隐式转换为‘`void’

Question

// Palindrome
using System;

class Mainclass{
  public static void Main(string[] args){
    string user_input = Console.ReadLine();
    char[] before_reversing = new char[user_input.Length];
    for(int i=0;i<user_input.Length;i++){
      before_reversing[i] = user_input[i];
    }
    char[] after_reversing = Array.Reverse(before_reversing);
    if (before_reversing == after_reversing) {
      Console.WriteLine("It is a palindrome");
    }
    else{
      Console.WriteLine("Not a palindrome");
    }
  }
}

由于出现错误，我无法运行代码...有人能帮我吗?我是C夏普编程新手。和练习我的编码技能，并陷入了回文。

Answer 1

这是因为Array.Reverse(Array)函数是一个空函数，在chars[]中没有返回值。为此，您可以像before_reversing一样放置after_reversing数组，然后反转它。看：

//Palindrome
using System;

class Mainclass{
  public static void Main(string[] args){
    string user_input = Console.ReadLine();
    char[] before_reversing = new char[user_input.Length];
    for(int i=0;i<user_input.Length;i++){
      before_reversing[i] = user_input[i];
    }
    char[] after_reversing = new char[before_reversing.Length];
    for(int i=0;i<before_reversing.Length;i++){
      after_reversing[i] = before_reversing[i];
    }
    Array.Reverse(after_reversing);
    if (before_reversing == after_reversing) {
      Console.WriteLine("It is a palindrome");
    }
    else{
      Console.WriteLine("Not a palindrome");
    }
  }
}