我有一个因子,它可以识别测量数据集中的地层。我想重新排序因子,以便某些字符模式优先于其他字符模式。
例如,我有一个表示性别、年龄和教育程度的混合因子:
my_factor <- factor(levels=c(1:8),
labels=c("Male-18_34-HS","Female-35_49-HS",
"Male-18_34-CG", "Female-18_34-CG",
"Male-35_49-HS", "Male-35_49-CG",
"Female-18_34-HS", "Female-35_49-CG"),
ordered=TRUE)我希望这是排序与所有女性类别首先,然后在正确的顺序年龄类别,然后在正确的顺序教育类别。我可以使用forcats::fct_relevel完成大部分工作。
forcats::fct_relevel(my_factor, sort)
ordered(0)
8 Levels: Female-18_34-CG < Female-18_34-HS < Female-35_49-CG < Female-35_49-HS < Male-18_34-CG < Male-18_34-HS < ... < Male-35_49-HS但教育类别的顺序是错误的。有没有办法确保"HS“在"CG”之前,但性别和年龄组的顺序相同?
发布于 2021-04-09 09:01:09
您可以创建一个参照表,按列系数级别排列:
library(dplyr)
library(tidyr)
ref <- tibble(key = c("Male-18_34-HS","Female-35_49-HS",
"Male-18_34-CG", "Female-18_34-CG",
"Male-35_49-HS", "Male-35_49-CG",
"Female-18_34-HS", "Female-35_49-CG"))
ref <- separate(ref, key, into = c("gender", "age", "education"), sep = "-", remove = FALSE) %>%
mutate(across("gender", factor, c("Female", "Male")),
across("age", factor, c("18_34", "35_49")),
across("education", factor, c("HS", "CG"))) %>%
arrange(gender, age, education)然后申请:
factor(d, levels = ref$key)
发布于 2021-04-09 10:50:25
您可以通过编程方式创建所需的因子级别。
lvls <- do.call(paste, c(tidyr::expand_grid(
c('Female', 'Male'), c('18_34', '35_49'), c('HS', 'CG')), sep = '-'))
lvls
#[1] "Female-18_34-HS" "Female-18_34-CG" "Female-35_49-HS" "Female-35_49-CG"
#[5] "Male-18_34-HS" "Male-18_34-CG" "Male-35_49-HS" "Male-35_49-CG"您可以在factor调用中将此lvls用作级别。
发布于 2021-04-09 13:07:05
您可以使用str_split拆分标签,对生成的列表进行排序,并相应地重建级别:
lvl <- do.call(rbind,stringr::str_split(levels(my_factor),'-'))
lvl <- apply(lvl[order(lvl[,1],lvl[,2],lvl[,3]),],1,paste0,collapse='-')
my_factor <- factor(my_factor,levels = lvl)
levels(my_factor)
#> [1] "Female-18_34-CG" "Female-18_34-HS" "Female-35_49-CG" "Female-35_49-HS"
#> [5] "Male-18_34-CG" "Male-18_34-HS" "Male-35_49-CG" "Male-35_49-HS"https://stackoverflow.com/questions/67013442
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