新手来了。
我正在尝试创建两个不同基因的基因表达式2^-DCT值(数据框中的p2ndCt)的抖动图,以及表示平均值的两条单独的线。我的样本是一系列有序的细胞系。我将数据放在data.frame中,如下所示:
Sample gene dCt p2ndCt
1 K562 naive e14a2 -1.34 2.531513e+00
2 DMSO ctrl e14a2 -0.40 1.319508e+00
3 0.5 nM e14a2 -1.93 3.810552e+00
4 1 nM e14a2 -3.06 8.339726e+00
5 2 nM e14a2 -4.17 1.800094e+01
6 3.5 nM e14a2 -4.70 2.599208e+01
7 5 nM e14a2 -3.58 1.195879e+01..。
67 5 nM e6a2 -2.06 4.169863e+00
68 10 nM e6a2 -0.02 1.013959e+00
69 15 nM e6a2 7.52 5.448217e-03
70 25 nM e6a2 0.75 5.946036e-01我想让stat_summary()在每个样本中分离e14a2均值和e6a2均值,但是我不确定如何在现有的data.frame中做到这一点。我尝试过以下代码:
##BCR-ABL1 dCt qPCR graph
BCRABL1_dCt <- read.csv('~/Manjaro/workspace/BCR-ABL1_dCt.csv')
BCRABL1_dCt$Sample <- factor(BCRABL1_dCt$Sample, levels = c('K562 naive', 'DMSO ctrl', '0.5 nM', '1 nM', '2 nM', '3.5 nM', '5 nM', '10 nM', '15 nM', '25 nM', '50 nM', '200 nM'))
BCRABL1_dCt_plot <- ggplot(BCRABL1_dCt, aes(x = Sample, y = p2ndCt, color = gene)) + geom_jitter(width = 0.1, height = 0) + stat_summary(aes(y = p2ndCt, group = 1), fun = mean, geom = 'line', size = 1, color = 'red')
e14a2_dCt_plot...which只给了我一条线,平均了这两个基因。我读到过,我可以把这些基因放在不同的data.frames中,但最好是全部放在一个one里。提前感谢您的帮助!
发布于 2021-04-02 19:42:42
使用所提供的数据片段运行您的代码,Sample提供了一种方法
library(ggplot2)
ggplot(BCRABL1_dCt, aes(x = Sample, y = p2ndCt, color = gene)) +
geom_jitter(width = 0.1, height = 0) +
stat_summary(aes(y = p2ndCt, group = 1), fun = mean, geom = 'line', size = 1, color = 'red')

但是,使用group=gene而不是group=1为每个gene提供了一系列方法
ggplot(BCRABL1_dCt, aes(x = Sample, y = p2ndCt, color = gene)) +
geom_jitter(width = 0.1, height = 0) +
stat_summary(aes(y = p2ndCt, group = gene), fun = mean, geom = 'line', size = 1, color = 'red')

DATA
BCRABL1_dCt <- read.table(text = " Sample gene dCt p2ndCt
1 K562_naive e14a2 -1.34 2.531513e+00
2 DMSO_ctrl e14a2 -0.40 1.319508e+00
3 0.5_nM e14a2 -1.93 3.810552e+00
4 1_nM e14a2 -3.06 8.339726e+00
5 2_nM e14a2 -4.17 1.800094e+01
6 3.5_nM e14a2 -4.70 2.599208e+01
7 5_nM e14a2 -3.58 1.195879e+01
67 5_nM e6a2 -2.06 4.169863e+00
68 10_nM e6a2 -0.02 1.013959e+00
69 15_nM e6a2 7.52 5.448217e-03
70 25_nM e6a2 0.75 5.946036e-01", header = TRUE)
BCRABL1_dCt$Sample <- gsub("_", " ", BCRABL1_dCt$Sample)
BCRABL1_dCt$Sample <- factor(BCRABL1_dCt$Sample, levels = c('K562 naive', 'DMSO ctrl', '0.5 nM', '1 nM', '2 nM', '3.5 nM', '5 nM', '10 nM', '15 nM', '25 nM', '50 nM', '200 nM'))https://stackoverflow.com/questions/66916060
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