Typescript:从对象的联合中提取文字

Question

我有一个对象的联合，如下所示

type NotificationState =
    | { kind: "dynamic"; state: "pending" }
    | { kind: "dynamic"; state: "deployingNodes" }
    | { kind: "dynamic"; state: "provisioningEndpoints" }
    | { kind: "dynamic"; state: "connecting" }
    | { kind: "dynamic"; state: "applyingCredentials" }
    | { kind: "static"; state: "online" }
    | { kind: "static"; state: "updating" }
    | { kind: "static"; state: "maintenance" }
    | { kind: "static"; state: "unknown" }

typescript是否支持通过过滤器创建新类型的方法？例如，我想创建一个kind为dynamic的类型

type DynamicNotificationState =
    | { kind: "dynamic"; state: "pending" }
    | { kind: "dynamic"; state: "deployingNodes" }
    | { kind: "dynamic"; state: "provisioningEndpoints" }
    | { kind: "dynamic"; state: "connecting" }
    | { kind: "dynamic"; state: "applyingCredentials" }

Answer 1

你想要这样的东西吗？

type DynamicNotificationState<T> =
    | { kind: T; state: "pending" }
    | { kind: T; state: "deployingNodes" }
    | { kind: T; state: "provisioningEndpoints" }
    | { kind: T; state: "connecting" }
    | { kind: T; state: "applyingCredentials" }

const v: DynamicNotificationState<'dynamic'> = {
    
}