如何在后台运行chokidar (persistent: true)？

Question

我正在编写一个node.js程序，需要监视(添加/删除/更新)文件夹中的文件。我正在使用chokidar来查看文件。下面是代码

async function updateIndexFile() {
    console.log({ path });
    const pathArray = []

    // Chokidar Code
    const options = {
      ignored: /(^|[\/\\])\../, // ignore dotfiles
      persistent: true
    }

    // Initialize watcher.
    const watcher = chokidar.watch(path, options);

    watcher
      .on('add', async (path) => {
        console.log(`File ${path} has been added`)
        let answer = await prompt({
          type: 'list',
          name: 'adventure',  // * Key
          message: 'Choose your own adventure',
          choices: ['Indexify', 'Undo'] // * Add Feature Names Here
        })
        console.log(answer);        
      })  // Run indexify again on these files
      .on('change', path => console.log(`File ${path} has been changed`)) // Run indexify again on these files
      .on('unlink', path => console.log(`File ${path} has been removed`));  // Run indexify again on these files

​

​

但是，我不能使用终端，因为chokidar正在看文件。所以，我想让chokidar在后台看文件。因此，我仍然可以提示用户提出更多问题，并做我自己的事情。

Answer 1

我知道我迟到了3个月，你现在可能已经找到了答案，但这是为后来访问的人准备的。您可以使用名为的节点模块来使用派生子进程。简单地将您代码放在一个文件中，并使用以下代码执行该文件

 const {spawn}=require(child_prcoess);
let detached_process = spawn(process.argv[0], ["program_name", "arg1","arg2","arg3"], { detached: true}); //launch program_name and detach it from program_name with args provided

            detached_process.unref(); //tell main program to do not wait for the completion of program_name