Pydroid能识别random.choice吗？

Question

以下是我的代码

user_action = input("enter rock, paper, or scissors:  ")
possible_action = ["rock", "paper", "scissors"]
computer_action = random.choice(possible_action)

它告诉我它是一个无效的变量。

是我做错了什么，还是Pydroid的错？

Answer 1

唯一可能的问题是您忘记了

导入随机

这段代码运行得非常好：

import random
user_action = input("enter rock, paper, or scissors:  ")
possible_action = ["rock", "paper", "scissors"]
computer_action = random.choice(possible_action)
print(computer_action)