我如何在C中构造我正在尝试构造的Othello板数组？

Question

我正在尝试用C编写一个基于文本的奥赛罗引擎，作为开始学习C的一种方式。我已经在高级语言中实现了这一点，所以我决定在C中尝试一下，因为基本的逻辑是正确的，并且可以工作。

我尝试将电路板表示为一个8x8数组，它可以使用一个函数动态重置。

板子应该是这样的：

* * * * * * * *
* * * * * * * *
* * * * * * * *
* * * w b * * *
* * * b w * * *
* * * * * * * *
* * * * * * * *
* * * * * * * *

我尝试将一个指向存储电路板的数组的指针传递到resetBoard函数中，这样我就可以随时重置电路板。怎样才能让线路板用相应的字符更新数组？

这就是我正在尝试的：

int resetBoard(char *board) {
    int i;
    int j;
    for (i = 0; i<8; i++) {
        for (j = 0; j<8; j++) {
            
            if ((i == 4 && j == 4) | (i == 5 && j == 5)) {
                board[i][j] = "w";
            } else if ((i == 5 && j == 4) | (i == 4 && j == 5)) {
                board[i][j] = "b";
            } else {
                board[i][j] = "*";
            }
        
        }
    }

    return 0;
}

void main() {
    char board[8][8];
    resetBoard(*board);

    for (int i = 0; i<8; i++) {
        for (int j = 0; j<8; j++) {
            char x = board[i][j];
            printf(" %c ", x);
        
        }
        printf("\n");
    }

}

当我尝试编译时，我得到了以下错误消息：

.\Othello.c: In function 'resetBoard':
.\Othello.c:10:25: error: subscripted value is neither array nor pointer nor vector
                 board[i][j] = "w";
                         ^
.\Othello.c:12:25: error: subscripted value is neither array nor pointer nor vector
                 board[i][j] = "b";
                         ^
.\Othello.c:14:25: error: subscripted value is neither array nor pointer nor vector
                 board[i][j] = "*";

我只是尝试将字符赋值给boardi，而不是boardi，但是它提供了这个错误：

.\Othello.c: In function 'resetBoard':
.\Othello.c:10:26: warning: assignment to 'char' from 'char *' makes integer from pointer without a cast [-Wint-conversion]
                 board[i] = "w";
                          ^
.\Othello.c:12:26: warning: assignment to 'char' from 'char *' makes integer from pointer without a cast [-Wint-conversion]
                 board[i] = "b";
                          ^
.\Othello.c:14:26: warning: assignment to 'char' from 'char *' makes integer from pointer without a cast [-Wint-conversion]
                 board[i] = "*";

所以我知道我有很多问题。我对C编程或任何低级编程都是完全陌生的，所以欢迎任何帮助！

非常感谢！

Answer 1

• 传递整个数组board (指向的第一个元素的指针)，而不是第一行。
• board的每个元素的元素都是char，因此应该使用字符常量，如'w'，而不是字符串文字

int resetBoard(char board[][8]) { /* change argument type to accept the whole array */
    int i;
    int j;
    for (i = 0; i<8; i++) {
        for (j = 0; j<8; j++) {
            
            if ((i == 4 && j == 4) | (i == 5 && j == 5)) {
                board[i][j] = 'w'; /* use character constant */
            } else if ((i == 5 && j == 4) | (i == 4 && j == 5)) {
                board[i][j] = 'b'; /* use character constant */
            } else {
                board[i][j] = '*'; /* use character constant */
            }
        
        }
    }

    return 0;
}

void main() {
    char board[8][8];
    resetBoard(board); /* pass the whole array */

    for (int i = 0; i<8; i++) {
        for (int j = 0; j<8; j++) {
            char x = board[i][j];
            printf(" %c ", x);
        
        }
        printf("\n");
    }

}

Answer 2

以下是建议的代码：

根据更改的原因，在每个更改的行上干净地为所需的functionality

• eliminates‘compiles

• performs’numbers

• appropriately设置垂直间隔的'main()'

• includes readability

• commented。

• 使用'logical‘OR而不是'bit wise’OR。

• 为包含‘main()’

• includes原型的头文件使用两个有效签名之一的printf()

(

1. ) #include

现在，建议的代码如下：

// note vertical spacing for readability
#include <stdio.h>  // added for 'printf()'

// to give 'magic' numbers meaningful names
#define ROWS 8  
#define COLS 8  


// return type modified as nothing uses the returned value
void resetBoard(char board[ROWS][COLS]) // valid parameter, which compiler needs
{ 
    int i;
    int j;
    
    for (i = 0; i< ROWS; i++)   // ROWS rather than 'magic' number
    {
        for (j = 0; j< COLS; j++)  // COLS rather than 'magic' number
        { 
            
            if ((i == 4 && j == 4) || (i == 5 && j == 5)) // || for logical OR
            {
                board[i][j] = 'w';  // 'w' for a single char rather than array
            } 
            
            else if ((i == 5 && j == 4) || (i == 4 && j == 5))  // || for logical OR
            {
                board[i][j] = 'b';  // 'b' for a single char rather than an array
            }
            
            else  // these lines modified to follow axiom:
                  // only one statement per line and (at most) one variable declaration per statement
            {
                board[i][j] = '*';  // '*' for a single char rather than an array
            }
        
        }
    }
}


int main( void )   // valid C signature for 'main()'
{
    char board[ROWS][COLS];    // rather than 'magic' numbers
    resetBoard(board);         // since 'board[][]' is array, bare reference degrades to address of first byte of array

    for (int i = 0; i<ROWS; i++)   // use meaningful name rather than 'magic' number
    { 
        for (int j = 0; j<COLS; j++)  // use meaningful name rather than 'magic' number
        { 
            char x = board[i][j];
            printf(" %c ", x);
        
        }
        printf("\n");
    }
}

运行建议的代码会产生以下结果：

 *  *  *  *  *  *  *  * 
 *  *  *  *  *  *  *  * 
 *  *  *  *  *  *  *  * 
 *  *  *  *  *  *  *  * 
 *  *  *  *  w  b  *  * 
 *  *  *  *  b  w  *  * 
 *  *  *  *  *  *  *  * 
 *  *  *  *  *  *  *  * 

注意:起始位置的偏移量1太低，1太右。这是因为在C中，数组从0开始，而不是1