如何在数据库中存储调度cron引用，以便将来在节点js中停止cron？

Question

我正在使用cron安排推送通知。我正在从用户那里收集推送通知数据和预定时间，以便在预定时间发送推送通知。

下面是我如何创建一个cron作业来调度推送通知：

const CronJob = require("cron").CronJob;
...
...
const schedulePushNotification = async (req, res) => {
  const job = new CronJob(
    new Date(req.body.scheduledTime),
    async () => {
      // my code to send push notification
      // code to store push notification data
      // Here I write a code to store push notification data to 
      // show on the dashboard like a list of notification
    },
    null,
    true,
    "America/Los_Angeles"
  );
  
  job.start();
  return res.status(200).json({
    success: true,
    message: "Notification has been scheduled successfully !",
    data: null,
  });
};

现在的要求是，如果用户想要取消预定的推送通知，他们可以通过单击cancel来完成。

那么，我该如何销毁正在运行的cron呢？

Answer 1

您可以通过在函数中添加一个if语句来实现这一点

您可以检查用户是否激活了通知，但首先必须将用户是否激活通知存储在数据库中，然后再发送通知

const CronJob = require("cron").CronJob;
...
...
const schedulePushNotification = async (req, res) => {
  const job = new CronJob(
    new Date(req.body.scheduledTime),
    async () => {



      let userNotificationDetails = getUserNotificationDetails();
      if(userNotificationDetails.isSendNotification){
          job.start();
      } else {
          // don't send notification
      }



      // my code to send push notification
      // code to store push notification data
      // Here I write a code to store push notification data to 
      // show on the dashboard like a list of notification
    },
    null,
    true,
    "America/Los_Angeles"
  );
  
  
  return res.status(200).json({
    success: true,
    message: "Notification has been scheduled successfully !",
    data: null,
  });
};

。

cron编辑(另一种解决方案:在启动之前检查是否isNotification )：

const CronJob = require("cron").CronJob;
...
...
const schedulePushNotification = async (req, res) => {
  const job = new CronJob(
    new Date(req.body.scheduledTime),
    async () => {
      // my code to send push notification
      // code to store push notification data
      // Here I write a code to store push notification data to 
      // show on the dashboard like a list of notification
    },
    null,
    true,
    "America/Los_Angeles"
  );



  let userNotificationDetails = getUserNotificationDetails();
  if(userNotificationDetails.isSendNotification){
      job.start();
  } else {
      // don't send notification
  }
  



  return res.status(200).json({
    success: true,
    message: "Notification has been scheduled successfully !",
    data: null,
  });
};

Answer 2

您可以通过在函数内添加一条if语句来完成此操作

您可以检查用户是否激活了通知，但首先必须在数据库中存储用户是否激活了通知，然后发送通知