我正在尝试通过multipart向服务器发送文件。它可以是图像,也可以是普通文件。我对URLConvertible的使用有一些困难。正如我所看到的,Alamofire有这样的方法,这可能对我有用:
AF.upload(multipartFormData: <(MultipartFormData) -> Void>, to: <URLConvertible>)但是在这里,因为你可以,我不能附加拦截器,它将处理401错误。为此,我创建了这样的变量:
let manager = Session(configuration: URLSessionConfiguration.default, interceptor: CallInterceptor.init(method:HTTPMethod.post))还创建了请求:
var request = URLRequest(url: Pathes.init(endpoint: "photo").resourseUrl)
request.httpMethod = HTTPMethod.post.rawValue最后的用法是附加在照片选择器上的:
func imagePickerController(_ picker: UIImagePickerController, didFinishPickingMediaWithInfo info: [UIImagePickerController.InfoKey : Any]) {
guard let fileUrl = info[UIImagePickerController.InfoKey.imageURL] as? URL else { return }
if let pickedImage = info[UIImagePickerController.InfoKey.originalImage] as? UIImage {
.....
manager.upload(multipartFormData: { (formData) in
formData.append(fileUrl, withName: "photo", fileName: fileName, mimeType: mediaType)
}, to: request as! URLConvertible).validate(statusCode: 200..<300)
.responseJSON(completionHandler: { (response) in
print(response.debugDescription)
})
}
}但结果是我的应用程序崩溃了,错误如下:
Could not cast value of type 'Foundation.URLRequest' (0x7fff85d1dbd8) to 'Alamofire.URLConvertible' (0x7ffb558a5320)我想我有两种方法:使用另一个AF方法或者创建另一个请求类型。但是我不能想象哪种方法一方面能帮到我,另一方面我又不知道如何创建URLConvertible。我想我可以这样做:
let urlRequest: Alamofire.URLRequestConvertible = request但这款应用程序再次崩溃。我做错了什么?
发布于 2021-01-25 12:07:15
如果您希望使用URLRequest而不是URL,则需要使用适当的upload重载:upload(multipartFormData:with:)。
manager.upload(multipartFormData: { (formData) in
formData.append(fileUrl, withName: "photo", fileName: fileName, mimeType: mediaType)
}, with: request)https://stackoverflow.com/questions/65878638
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