Python中的问题(Try、Finally和Except)

Question

我试图得到一个准确的年龄，但这不起作用，它给了我错误，有时还会重复。我已经试着让它工作几个小时了。但我想问题出在finally上。我尝试了except，但它只给我错误。我该怎么解决它呢？

end04 = False                      
while not end04:
    Age = input("Age: ")
    try:
        int(Age)
        end04 = True
    finally:
        if Age[-1:] == 'w':
            Age.replace('w','')
            int(Age)
            Age /= 52
            end04 = True
        elif Age[-1:] == 'm':
            Age.replace('m', '')
            int(Age)
            Age /= 12
            end04 = True
        else:
            end04 = False
            print("Only enter m or w after number or just number")

如果我放在最后，它只是重复说“只在数字后面输入m或w，或者只输入数字”。

如果我put except，它会给出一个错误(当我输入3M时)

int(Age) ValueError:基数为10的int()的文本无效：'3m‘

Answer 1

end04 = False                      
while not end04:
    Age = input("Age: ")
    try:
        int(Age)
        end04 = True
    except ValueError: # Here your are trying to catch the Exception (when m/w in input), so you need to use except with the Exception you want to catch
        if Age[-1:] == 'w':
            Age = Age.replace('w','') # string.replace function return's the replaced string therefore need to assign it back to Age Variable.
            Age = int(Age) # similarly int() also returns the type casted value.
            Age /= 52
            end04 = True
        elif Age[-1:] == 'm':
            Age = Age.replace('m', '')
            Age = int(Age)
            Age /= 12
            end04 = True
        else:
            end04 = False
            print("Only enter m or w after number or just number")

我已经修复了你的代码。

也要调查一下，

如果所有字符都是数字(0-9)，则

1. string.isnumeric()方法返回True，否则返回False。尝试使用它，而不是使用Try execute。
2. 块允许您执行代码，而不管try-
3. except块的结果如何。但是在您的示例中，您希望在输入中有字符时捕获异常，因此在这里使用except是合适的。

Answer 2

这就是你的最终程序的样子，以更简单的方式处理所有类型的输入。

import re

end04 = False
divider = 1
while not end04:
    Age = input("Age: ")
    try:
        age = re.findall(r'\d+\w', Age)
        if len(age) > 0:
            letter = age[0][-1]
            if letter.isnumeric() or (letter in ['w', 'm']):
                if letter in ['w', 'm']:
                    age = int(age[0][:-1])
                    divider = 12
                    if letter == 'w':
                        divider = 52

                else:
                    age = int(age[0])
                print('age', age)
                age /= divider
                print('output', age)
                end04 = True
    finally:
        if not end04:
            print("Only enter m or w after number or just number")

输出：

Age: 32
age 32
output 32.0

Age: 32w
age 32
output 0.6153846153846154

Age: 32m
age 32
output 2.6666666666666665