Centroid不接受用户输入的代码

Question

我目前正在处理一个项目，在该项目中，我需要获取用户输入，然后使用该输入计算三角形的质心。三角形的长度来自用户的输入。由于某些原因，公式不接受用户输入。

import java.util.Scanner;

public class Centroid {

    public static void main(String[] args) {
        // coordinate of the vertices 
        Scanner bucky = new Scanner(System.in);
        System.out.println("Please enter variables for x1:");
        String x1 = bucky.nextLine();
        System.out.println("Please enter variables for x2:");
        String x2 = bucky.nextLine();
        System.out.println("Please enter variables for x3:");
        String x3 = bucky.nextLine();
        System.out.println("Please enter variables for y1:");
        String y1 = bucky.nextLine();
        System.out.println("Please enter variables for y2:");
        String y2 = bucky.nextLine();
        System.out.println("Please enter variables for y3:");
        String y3 = bucky.nextLine();
        
     
      
        // Formula to calculate centroid 
        float x = (x1 + x2 + x3) / 3; 
        float y = (y1 + y2 + y3) / 3; 
      
        System.out.println("Centroid = "
        + "(" + x + ", " + y + ")"); 
    }

}

Answer 1

您使用字符串作为质心值，应使用浮点型、整型、双精度或短整型等数值变量，这就是公式不起作用的原因

尝试浮点变量

public class Centroid {

    public static void main(String[] args) {
        // coordinate of the vertices 
        Scanner bucky = new Scanner(System.in);
        System.out.println("Please enter variables for x1:");
        float x1 = bucky.nextFloat();
        System.out.println("Please enter variables for x2:");
        float x2 = bucky.nextFloat();
        System.out.println("Please enter variables for x3:");
        float x3 = bucky.nextFloat();
        System.out.println("Please enter variables for y1:");
        float y1 = bucky.nextFloat();
        System.out.println("Please enter variables for y2:");
        float y2 = bucky.nextFloat();
        System.out.println("Please enter variables for y3:");
        float y3 = bucky.nextFloat();



        // Formula to calculate centroid 
        float x = (x1 + x2 + x3) / 3;
        float y = (y1 + y2 + y3) / 3;

        System.out.println("Centroid = "
                + "(" + x + ", " + y + ")");
    }
} 

Answer 2

您正在尝试除以字符串的和解决方案是使变量( x1，x2，x3等)浮动；将：“strings.The x1 = bucky.nextLine();”改为："float x1= bucky.nextFloat();“。

public class Centroid{

public static void main(String[] args) {
// coordinate of the vertices 
Scanner bucky = new Scanner(System.in);
System.out.println("Please enter variables for x1:");
float x1 = bucky.nextFloat();
System.out.println("Please enter variables for x2:");
float x2 = bucky.nextFloat();
System.out.println("Please enter variables for x3:");
float x3 = bucky.nextFloat();
System.out.println("Please enter variables for y1:");
float y1 = bucky.nextFloat();
System.out.println("Please enter variables for y2:");
float y2 = bucky.nextFloat();
System.out.println("Please enter variables for y3:");
float y3 = bucky.nextFloat();



// Formula to calculate centroid 
float x = (x1 + x2 + x3)/ 3; 
float y = (y1 + y2 + y3)/ 3; 

System.out.println("Centroid = "
+ "(" + x + ", " + y + ")"); 
}

}