在这个程序中,我创建了一个名为mydata的数据库,创建了一个名为mining的表,我想从列表中读取我的姓名和年龄,如果它不在数据库中,则将其保存在数据库中。但是我遇到了麻烦,我的程序给出了一个错误。
实际上,在编写SQL语法时,如果数据不存在,它会将数据存储在数据库中。我有个问题
mycode:
import mysql.connector
cnx = mysql.connector.connect(
host='localhost',
user = 'root',
password = '',
database = 'mydata'
)
c = cnx.cursor()
list_number = ['mobin','ghanbari',15]
for i in list_number:
c.execute('INSERT INTO mining VALUES ("%s","%s","%s") WHERE NOT EXISTS (SELECT * FROM mining)'%(i,i,i))请帮我解决这个问题
发布于 2021-01-14 04:28:10
您需要为不想重复的字段添加唯一索引
下面是一个包含3个字段的示例。您可以使用多个字段
mysql> ALTER TABLE mining ADD UNIQUE INDEX(your_field1, your_field2,your_field3);并使用INSERT忽略而不是INSERT。这将阻止查询在表中插入相同的数据两次或多次
for i in list_number:
c.execute('INSERT IGNORE INTO mining VALUES ("%s","%s","%s") )或执行查询:
SELECT * FROM mining WHERE
your_field1 = 'mobin' AND
your_field2 = 'ghanbari' AND
your_field3 = 15;在查询插入之前。
如果SELECT查询返回某些内容,则不执行INSERT查询。否则,执行插入查询。
发布于 2021-01-14 09:02:36
访问mysql
$ mysql -u root -p 以mysql为例,从命令行创建数据库和表。
mysql> CREATE DATABASE sof;查询正常,1行受影响(0.00秒)
mysql> use sof;数据库已更改
mysql> CREATE TABLE mining (
-> id int NOT NULL AUTO_INCREMENT,
-> lastname varchar(255) NOT NULL,
-> firstname varchar(255),
-> age int,
-> PRIMARY KEY (id)
-> );查询正常,0行受影响(0.01秒)
mysql> show tables;
+---------------+
| Tables_in_sof |
+---------------+
| mining |
+---------------+
mysql> explain mining;
+-----------+--------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+-----------+--------------+------+-----+---------+----------------+
| id | int(11) | NO | PRI | NULL | auto_increment |
| lastname | varchar(255) | NO | | NULL | |
| firstname | varchar(255) | YES | MUL | NULL | |
| age | int(11) | YES | | NULL | |
+-----------+--------------+------+-----+---------+----------------+
4 rows in set (0.00 sec)
mysql> ALTER TABLE mining ADD UNIQUE INDEX(firstname, lastname, age);查询正常,0行受影响(0.02秒)记录:0重复:0警告:0
mysql> SHOW INDEXES FROM mining;
+--------+------------+-----------+--------------+-------------+-----------+-------------+----------+--------+------+------------+---------+---------------+
| Table | Non_unique | Key_name | Seq_in_index | Column_name | Collation | Cardinality | Sub_part | Packed | Null | Index_type | Comment | Index_comment |
+--------+------------+-----------+--------------+-------------+-----------+-------------+----------+--------+------+------------+---------+---------------+
| mining | 0 | PRIMARY | 1 | id | A | 2 | NULL | NULL | | BTREE | | |
| mining | 0 | firstname | 1 | firstname | A | 2 | NULL | NULL | YES | BTREE | | |
| mining | 0 | firstname | 2 | lastname | A | 2 | NULL | NULL | | BTREE | | |
| mining | 0 | firstname | 3 | age | A | 3 | NULL | NULL | YES | BTREE | | |
+--------+------------+-----------+--------------+-------------+-----------+-------------+----------+--------+------+------------+---------+---------------+
4 rows in set (0.00 sec)如果索引可以包含重复项,请注意字段Non_unique 1;如果不能包含重复项,请注意字段0。
现在是脚本:
import mysql.connector
mydb = mysql.connector.connect(
host='localhost',
user = 'root',
password = '',
database = 'sof'
)
cursor = mydb.cursor()
listd =[
{'firstname':'mobin1','lastname':'ghanbari1','age':15},
{'firstname':'mobin2','lastname':'ghanbari2','age':16},
{'firstname':'mobin3','lastname':'ghanbari3','age':17},
{'firstname':'mobin4','lastname':'ghanbari4','age':18}
]
for row in listd:
sql = "INSERT INTO mining (firstname, lastname , age) VALUES (%s, %s, %s)"
val = (row['firstname'],row['lastname'], row['age'])
try:
cursor.execute(sql, val)
mydb.commit()
print(cursor.rowcount, "record inserted for "+row["firstname"])
except mysql.connector.Error as err:
print("mysql exception: {}".format(err))
print(cursor.rowcount, "record inserted for "+row["firstname"])输出:
1 record inserted for mobin1
1 record inserted for mobin2
1 record inserted for mobin3
1 record inserted for mobin4如果插入了记录,则在mysql上进行检查
mysql> select * from mining;
+----+-----------+-----------+------+
| id | lastname | firstname | age |
+----+-----------+-----------+------+
| 1 | ghanbari1 | mobin1 | 15 |
| 2 | ghanbari2 | mobin2 | 16 |
| 3 | ghanbari3 | mobin3 | 17 |
| 4 | ghanbari4 | mobin4 | 18 |
+----+-----------+-----------+------+
4 rows in set (0.00 sec)在Python脚本*的列表中添加一些数据
import mysql.connector
mydb = mysql.connector.connect(
host='localhost',
user = 'root',
password = '',
database = 'sof'
)
cursor = mydb.cursor()
listd =[
{'firstname':'mobin1','lastname':'ghanbari1','age':15},
{'firstname':'mobin2','lastname':'ghanbari2','age':16},
{'firstname':'mobin3','lastname':'ghanbari3','age':17},
{'firstname':'mobin4','lastname':'ghanbari4','age':18},
{'firstname':'mobin5','lastname':'ghanbari5','age':19},
{'firstname':'mobin6','lastname':'ghanbari6','age':20},
{'firstname':'mobin7','lastname':'ghanbari7','age':21}
]
for row in listd:
sql = "INSERT INTO mining (firstname, lastname , age) VALUES (%s, %s, %s)"
val = (row['firstname'],row['lastname'], row['age'])
try:
cursor.execute(sql, val)
mydb.commit()
print(cursor.rowcount, "record inserted for "+row["firstname"])
except mysql.connector.Error as err:
print("mysql exception: {}".format(err))
print(cursor.rowcount, "record inserted for "+row["firstname"])运行Python脚本的
输出:
mysql exception: 1062 (23000): Duplicate entry 'mobin1-ghanbari1-15' for key 'firstname'
-1 record inserted for mobin1
mysql exception: 1062 (23000): Duplicate entry 'mobin2-ghanbari2-16' for key 'firstname'
-1 record inserted for mobin2
mysql exception: 1062 (23000): Duplicate entry 'mobin3-ghanbari3-17' for key 'firstname'
-1 record inserted for mobin3
mysql exception: 1062 (23000): Duplicate entry 'mobin4-ghanbari4-18' for key 'firstname'
-1 record inserted for mobin4
1 record inserted for mobin5
1 record inserted for mobin6
1 record inserted for mobin7检查mysql上是否有重复的条目
mysql> select * from mining;
+----+-----------+-----------+------+
| id | lastname | firstname | age |
+----+-----------+-----------+------+
| 1 | ghanbari1 | mobin1 | 15 |
| 2 | ghanbari2 | mobin2 | 16 |
| 3 | ghanbari3 | mobin3 | 17 |
| 4 | ghanbari4 | mobin4 | 18 |
| 13 | ghanbari5 | mobin5 | 19 |
| 14 | ghanbari6 | mobin6 | 20 |
| 15 | ghanbari7 | mobin7 | 21 |
+----+-----------+-----------+------+
7 rows in set (0.00 sec)如您所见,表中没有重复的条目。
https://stackoverflow.com/questions/65708884
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