mongoose find查询执行多个条件

Question

我有两个表供应商和vendorOrg表。我需要返回基于vendorOrg表标准和类别-wise的列表

const vendors = [{
  "name" : "Alfred",
  "location" : "FH",
  "vendorOrgId" : "1"
},
{
  "name" : "Alfred",
  "location" : "ADH",
  "vendorOrgId" : "2"
},
{
  "name" : "Alfred",
  "location" : "AFF",
  "vendorOrgId" : "41"
}]

const vendorOrg = [
  {
    "orgName" : "star super market",
    "vendorOrgId" : "1",
    "category" : "grocery",
    "status" : "active"
  },
  {
    "orgName" : "L.f super market",
    "vendorOrgId" : "41",
    "category" : "grocery",
    "status" : "active"
  },
  {
    "orgName" : "Fresh mart",
    "vendorOrgId" : "2",
    "category" : "Milk",
    "status" : "active"
  }
]

查找以下条件，1.供应商的表vendorOrgId必须与vendorOrg的表id相同。2. vendorOrg表状态应为active。如果上述条件成立，则i需要基于vendorOrg的表类别的供应商列表类别。

{
    "grocery": [{
            "name": "Alfred",
            "location": "FH",
            "vendorOrgId": "1"
        },
        {
            "name": "Alfred",
            "location": "AFF",
            "vendorOrgId": "41"
        }
    ],
    "milk": [{
        "name": "Alfred",
        "location": "ADH",
        "vendorOrgId": "2"
    }]
}

这对mongoose来说是可能的吗？谢谢!

Answer 1

• $lookup带有根集合，并传递
  • $lookup以查找pipeline
  • $match所需的conditions
  • $project以显示所需的fields
  • $unwind通过null解构array
  • $group并构造vendors
  • $group的数组并在键值format
  • $arrayToObject中构造数组将键值对数组转换为object
  • $replaceRoot以将对象替换为根

db.vendors.aggregate([
  {
    $lookup: {
      from: "vendorOrg",
      let: { vendorOrgId: "$vendorOrgId" },
      pipeline: [
        {
          $match: {
            $expr: { $eq: ["$$vendorOrgId", "$vendorOrgId"] },
            status: "active"
          }
        },
        { $project: { _id: 1, category: 1 } }
      ],
      as: "org"
    }
  },
  { $unwind: "$org" },
  {
    $group: {
      _id: "$org.category",
      vendors: {
        $push: {
          name: "$name",
          location: "$location",
          vendorOrgId: "$vendorOrgId"
        }
      }
    }
  },
  {
    $group: {
      _id: null,
      vendors: { $push: { k: "$_id", v: "$vendors" } }
    }
  },
  { $replaceRoot: { newRoot: { $arrayToObject: "$vendors" } } }
])

Playground