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“标识符中的无效字符”语法错误Python
EN

Stack Overflow用户
提问于 2021-01-01 05:54:15
回答 1查看 397关注 0票数 0

这是我的代码,它得到了语法错误"Invalid Character in Identifier“。我想不出怎么解决这个问题。如果能得到任何帮助,我将不胜感激。

代码语言:javascript
复制
    def number_to_words(n):
      if n == 0:
        return "zero"
  ​
      unit = ("", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine")
      tens = ("", "", "twenty", "thirty", "forty", "fifty", "sixty", "seventy", "eighty", "ninety")
      teen = ("ten", "eleven", "twelve", "thirteen", "fourteen", "fifteen", "sixteen", "seventeen", 
             "eighteen", "nineteen")
      h, t, u = ("", "", "")
  ​
      if n//100:
        h = unit[n//100] + " hundred"
        n = n%100
    ​
      if n >= 20:
        t = tens[n//10]
        n = n%10
      
      elif n >= 10:
        t = teen[n-10]
        n = 0

      u = unit[n]

      return " ".join(filter(None,[h,t,u]))

    number_to_words()
EN

回答 1

Stack Overflow用户

发布于 2021-01-01 06:00:36

在示例文本中有宽度为零的空格,甚至可能在原始代码中有更多非标准字符(在这里发布之前)。这可能是因为使用了像Word或WordPad这样的编辑器来编写代码。

使用适当的文本编辑器(如Notepad++或UltraEdit )或适当的集成开发环境(如PyCharm或VSCode )来编写代码。它有很多好处,其中之一就是避免了这些问题。

下面的代码删除了特殊字符并调整了间距,运行正常:

代码语言:javascript
复制
def number_to_words(n):
    if n == 0:
        return "zero"

    unit = ("", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine")
    tens = ("", "", "twenty", "thirty", "forty", "fifty", "sixty", "seventy", "eighty", "ninety")
    teen = ("ten", "eleven", "twelve", "thirteen", "fourteen", "fifteen", "sixteen", "seventeen",
            "eighteen", "nineteen")
    h, t, u = ("", "", "")

    if n // 100:
        h = unit[n // 100] + " hundred"
        n = n % 100

    if n >= 20:
        t = tens[n // 10]
        n = n % 10

    elif n >= 10:
        t = teen[n - 10]
        n = 0

    u = unit[n]

    return " ".join(filter(None, [h, t, u]))


print(number_to_words(10))
票数 0
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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/65525818

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