因此,我在脚本中使用了分形指示器,但我需要在警报中返回最后一个分形值。为此,我需要每根蜡烛返回最后一个分形信号的值(请不是我现在没有放入最高()和最低()函数,但我会的)
下面是我的代码:
fTop = high[4] < high[2] and high[3] < high[2] and high[2] > high[1] and high[2] > high[0]
fBottom= low[4] > low[2] and low[3] > low[2] and low[2] < low[1] and low[2] < low[0]
plotshape(fTop ? close : na, title='Top Fractals', style=shape.triangleup, location=location.abovebar, color=color.red, offset=-2)
plotshape(fBottom ? close : na, title='Bottom Fractals', style=shape.triangledown, location=location.belowbar, color=color.blue, offset=-2)
现在,如果我没有达到candle的条件,脚本会返回"na“。我试图把fTop1 / fBottom1,但它返回的最后一支蜡烛,而不是最后的条件...有谁有解决方案吗?
谢谢您:)
发布于 2021-01-06 05:50:03
我需要返回最后一个分形值
下面的解决方案将绘制分形的收盘价。请注意,您的分形有一个负的偏移量2,因此关闭系列有一个2巴的历史参考。
//@version=4
study("Fractal", overlay = true)
fTop = high[4] < high[2] and high[3] < high[2] and high[2] > high[1] and high[2] > high[0]
fBottom= low[4] > low[2] and low[3] > low[2] and low[2] < low[1] and low[2] < low[0]
plotshape(fTop ? close : na, title='Top Fractals', style=shape.triangleup, location=location.abovebar, color=color.red, offset=-2)
plotshape(fBottom ? close : na, title='Bottom Fractals', style=shape.triangledown, location=location.belowbar, color=color.blue, offset=-2)
var float fixTop = na
var float fixBot = na
if fTop
fixTop := close[2]
else if fBottom
fixBot := close[2]
plot(fixTop, change(fixTop) ? na : color.green, style = plot.style_linebr, offset = -2)
plot(fixBot, change(fixBot) ? na : color.red, style = plot.style_linebr, offset = -2)

要返回分形的高/低值,请更改代码的以下部分:
if fTop
fixTop := high[2]
else if fBottom
fixBot := low[2]

https://stackoverflow.com/questions/65580406
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