需要从列表中删除x个数的字符

Question

我的清单是这样的：

lst = [['^160magenta'], ['S159magenta', '//159magenta'], ['R158black', 'S158black', 'T158black'], ['S157black', 'T157yellow'], ['//156yellow']]

我希望它看起来像这样：

lst = [['magenta'], ['magenta', 'magenta'], ['black', 'black', 'black'], ['black', 'yellow'], ['yellow']]

它们是动态的，可以是不同的坐标和颜色。我有从选择器开始列出的所有颜色，所以我可以在每个列表中搜索这样的颜色，但idk如果有更简单的方法。

Answer 1

import re
lst = [['^160magenta'], ['S159magenta', '//159magenta'], ['R158black', 'S158black', 'T158black'], ['S157black', 'T157yellow'], ['//156yellow']]
for i in lst:
    for j in i:
        print(re.findall(r'\d+(.*)', j))

这会导致

['magenta']
['magenta']
['magenta']
['black']
['black']
['black']
['black']
['yellow']
['yellow']

Answer 2

import re

pattern = "[a-z]+"
data = [
    ["^160magenta"],
    ["S159magenta", "//159magenta"],
    ["R158black", "S158black", "T158black"],
    ["S157black", "T157yellow"],
    ["//156yellow"],
]

sorted_data = list()
for row in data:
    new_row = list()
    for word in row:
        match = re.findall(pattern, word)
        new_row.extend(match)

    sorted_data.append(new_row)

print(sorted_data)

Answer 3

尝尝这个

lst = [['^160magenta'], ['S159magenta', '//159magenta'], ['R158black', 'S158black', 'T158black'], ['S157black', 'T157yellow'], ['//156yellow']]
import re
lst=[[re.search('([a-z]{2,})',i).group(0) for i in j] for j in lst]
print(lst)

解释：

它搜索2个或更多的字母表，并将它们放入列表中，它还使用列表理解遍历原始列表两次，非列表理解版本将是：

lst = [['^160magenta'], ['S159magenta', '//159magenta'], ['R158black', 'S158black', 'T158black'], ['S157black', 'T157yellow'], ['//156yellow']]
temp=[]
for j in lst:
  for i in j:
    temp.append(re.search('([a-z]{2,})',i).group(0))

print(temp)