你好,我在谷歌上找不到解决方案。
然后“电话号码”移到下一行。就像这个
“注册”“主页”“联系人,电话号码=>移动到下一行”
我的问题是如何将一行中的联系人、电话号码作为菜单列表对齐。谢谢
.nav-li {
display: block;
padding: 20px 30px;
}<ul class="nav-links">
<li class="nav-li">
<!-- svelte-ignore a11y-invalid-attribute -->
<a href="#">Sign up</a>
</li>
<li class="nav-li">
<!-- svelte-ignore a11y-invalid-attribute -->
<a href="#">Home</a>
</li>
<li class="nav-li">
<!-- svelte-ignore a11y-invalid-attribute -->
<a href="#">Contact, Phone number</a>
</li>
</ul>
发布于 2020-08-19 16:33:37
https://jsfiddle.net/0bc7azed/3/
使用<p>或
<br>代码
<ul class="nav-links" >
<li class="nav-li">
<!-- svelte-ignore a11y-invalid-attribute -->
<a href="#">Sign up</a>
</li>
<li class="nav-li">
<!-- svelte-ignore a11y-invalid-attribute -->
<a href="#">Home</a>
</li>
<li class="nav-li">
<!-- svelte-ignore a11y-invalid-attribute -->
<a href="#">Contact,<br>Phone number</a>
</li>
</ul>发布于 2020-08-19 16:36:00
您可以使用<br>标记来换行。您也可以通过@FiveFour_Xone检查答案
.nav-li {
display: block;
padding: 20px 30px;
}<ul class="nav-links">
<li class="nav-li">
<!-- svelte-ignore a11y-invalid-attribute -->
<a href="#">Sign up</a>
</li>
<li class="nav-li">
<!-- svelte-ignore a11y-invalid-attribute -->
<a href="#">Home</a>
</li>
<li class="nav-li">
<!-- svelte-ignore a11y-invalid-attribute -->
<a href="#">Contact, <br />Phone number</a>
</li>
</ul>
发布于 2020-08-19 16:37:22
我希望这能对你有所帮助。
.nav-li{
display: block;
padding: 20px 30px;
}
.nav-li a {
text-decoration: none;
border-bottom: 1px solid #00f;
}<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<meta name="viewport" content="width=device-width, initial-scale=1.0">
<meta http-equiv="X-UA-Compatible" content="ie=edge">
<title>Document</title>
</head>
<body>
<ul class="nav-links" >
<li class="nav-li">
<!-- svelte-ignore a11y-invalid-attribute -->
<a href="#">Sign up</a>
</li>
<li class="nav-li">
<!-- svelte-ignore a11y-invalid-attribute -->
<a href="#">Home</a>
</li>
<li class="nav-li">
<!-- svelte-ignore a11y-invalid-attribute -->
<a href="#">Contact, Phone number</a>
</li>
</ul>
</body>
</html>
https://stackoverflow.com/questions/63482933
复制相似问题