在定义的函数中访问电池百分比时需要解决此问题

Question

如果我使用下面的代码，我可以很容易地访问battery.percent

from psutil import sensors_battery
battery = sensors_battery()
print('Current Battery : ' + battery.percent + '% charge')

我对通过定义函数来访问battery.percent感到困惑。

from psutil import sensors_battery
from datetime import datetime

def tab():
    battery = sensors_battery()
    now = datetime.now()
    return battery, now

print('Current Battery : ' + battery.percent + '% charge')
pluggin_disc = time(now.hour, now.minute)
battery_disc = battery.percent

print('Your battery have ' + str(battery_disc) + '% \n Current Time is : ', pluggin_disc, '\n')

Answer 1

你需要调用你的函数。否则，python不知道您所说的battery.percent是什么意思。

例如。

def tab():
    battery = sensors_battery()
    now = datetime.now()
    return battery, now

battery, now = tab()
print(... battery.percent ...)