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继承Python类的属性系统
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Stack Overflow用户
提问于 2020-08-27 06:36:36
回答 1查看 21关注 0票数 0
代码语言:javascript
复制
class Board:

    array = [[" ", " ", " "],
             [" ", " ", " "],
             [" ", " ", " "]]

    def reset(self):
        self.array = [[" ", " ", " "],
                      [" ", " ", " "],
                      [" ", " ", " "]]


class AI(Board):

    def __init__(self):
        self.array[0][0] = "X"


ai = AI()
board = Board() 
print(ai.array)  # [['X', ' ', ' '], [' ', ' ', ' '], [' ', ' ', ' ']]
print(board.array)  # [['X', ' ', ' '], [' ', ' ', ' '], [' ', ' ', ' ']]
ai.reset()
print(ai.array)  # [[' ', ' ', ' '], [' ', ' ', ' '], [' ', ' ', ' ']]
print(board.array)  # [['X', ' ', ' '], [' ', ' ', ' '], [' ', ' ', ' ']]

我的问题是,为什么ai.array改变了,而board.array改变了。如果它们是相互连接的,那么为什么当方法属于AI时,这两个属性没有一起更改。

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回答 1

Stack Overflow用户

发布于 2020-08-27 07:01:12

这可以通过以下方式来理解:

  • When you self.array to use or modify,如在expression self.array[0][0] = "X"中,然后单击

代码语言:javascript
复制
- first the instance is checked to see if it has such an attribute;
- if it does not, the type of the instance is checked for the attribute.

(这是对发生的事情的简化,但对于这种情况,您只需要知道这些)

表达式设置实例时,如您在

  • self.array = [...]中所做的那样,您将直接在instance

上设置属性

所以在你的示例代码中:

代码语言:javascript
复制
print(ai.array)     # ai does not have an array, Board.array is returned
print(board.array)  # board does not have an array, Board.array is returned
ai.reset()          # this adds an attribute to ai
print(ai.array)     # ai **does** have an array, it is returned
print(board.array)  # board does not have an array, Board.array is returned
票数 1
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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/63606661

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