忽略第一个单词的Javascript排序单词数组

Question

我有一个像下面这样的单词数组：

arr = ["id1 abc test", "id#2 XX car house", "id-3 abc home"]

我想对它进行排序，但忽略了第一个单词。例如，输出将是：

arr = ["id-3 abc home", "id1 abc test", "id#2 XX car house"]

谢谢

Answer 1

​

function getStringWithoutFirstWord(str) {
  return str.split(/\s+/).slice(1).join(' ');
}

function compareLoacallyWhilstIgnoringFirstWord(a, b) {
  a = getStringWithoutFirstWord(a); // yes, this is a ...
  b = getStringWithoutFirstWord(b); // ... highly repetitive task.
  return a.localeCompare(b);
}
function compareStronglyAscendingWhilstIgnoringFirstWord(a, b) {
  a = getStringWithoutFirstWord(a);  // yes, this is a ...
  b = getStringWithoutFirstWord(b); // ... highly repetitive task.
  return ((a < b && -1) || (a > b && 1) || 0);
}

const arr = ["id1 abc test", "id#2 XX car house", "id-3 abc home"];


console.log(
  arr.sort(compareLoacallyWhilstIgnoringFirstWord)
);
console.log(
  arr.sort(compareStronglyAscendingWhilstIgnoringFirstWord)
);

.as-console-wrapper { min-height: 100%!important; top: 0; }

​

..。Hassan Imam已经提到的方法的一个工作实现……

​

function getStringWithoutFirstWord(str) {
  return str.split(/\s+/).slice(1).join(' ');
}

function restoreStringFromDecoratedIgnoredFirstWordData(data) {
  return data.original;
}
function createDecoratedIgnoredFirstWordData(str) {
  return {
    original: str,
    sortable: getStringWithoutFirstWord(str)
  }
}

function compareSortablesLoacally(a, b) {
  return a.sortable.localeCompare(b.sortable);
}
function compareSortablesStronglyAscending(a, b) {
  a = a.sortable;
  b = b.sortable;
  return ((a < b && -1) || (a > b && 1) || 0);
}

const arr = ["id1 abc test", "id#2 XX car house", "id-3 abc home"];


console.log(arr
  .map(createDecoratedIgnoredFirstWordData)
  .sort(compareSortablesLoacally)
  .map(restoreStringFromDecoratedIgnoredFirstWordData)
);

console.log(arr
  .map(createDecoratedIgnoredFirstWordData)
  .sort(compareSortablesStronglyAscending)
  .map(restoreStringFromDecoratedIgnoredFirstWordData)
);

.as-console-wrapper { min-height: 100%!important; top: 0; }

​

Answer 2

这可以用常规的Array.prototype.sort和一个忽略第一个单词的小正则表达式来完成：

​

const arr = ["id1 abc test", "id#2 XX car house", "id-3 abc home"]

const result = arr.sort((a,b) => {

  const [aStr, bStr] = [a,b].map(l => l.replace(/^\S+/g,''));

  return aStr.localeCompare(bStr)

})

console.log(result);

​