我想知道在游戏中重复while循环是如何工作的

Question

这段代码在游戏开始时在地图上的某个区域内生成100只鸡，但其中一只玩家已经收集了所有的100只鸡，没有剩余的鸡可以收集，所以我想知道如何重新生成另外100只鸡，一旦剩余的鸡数量降到10只，那么玩家将有一个连续数量的鸡收集，希望这是有意义的，提前谢谢。jp

local newChicken = game.ServerStorage:FindFirstChild("ChickenOnePart")

local TopLeftCorner = Vector3.new(-187.64, 20.679, 106.2)
local BottomRightCorner = Vector3.new(201.12, 20.679, -241.45)
local numberOfChickens = 100
local counter = 0

local singleTonRandom = Random.new(tick())

local function GetRandom(Min,Max)
return singleTonRandom:NextNumber(Min,Max)
end


while counter < numberOfChickens  do
local chicken = newChicken:Clone()
chicken.Anchored = true
chicken.Parent = game.Workspace
chicken.Name = "Chicken"
chicken.Position = Vector3.new(
    GetRandom(TopLeftCorner.X,BottomRightCorner.X),
    4,
    GetRandom(TopLeftCorner.Z,BottomRightCorner.Z)
)
counter = counter + 1

end 

这段代码在玩家每次触摸一只鸡时将计数器加1。我能从这里得到当前的鸡肉数量吗？

if hitPart.Name == "Chicken" then
    event:FireServer(hitPart)
    local currentcount = playerGUI.ChickenGui.ChickenCounter.Text
    playerGUI.ChickenGui.ChickenCounter.Text = currentcount + 1
    hitPart:Destroy()
    debounce = true
    wait(0.1)
    debounce  = false
end
end)

这是用于更新前导的代码。

local event = Instance.new("RemoteEvent")
event.Name = "CurrencyAdd"
event.Parent = game.ReplicatedStorage

event.OnServerEvent:Connect(function(plr,part)
local currency = plr.leaderstats.Chickens
currency.Value = currency.Value + 1
end)


game.Players.PlayerAdded:Connect(function(plr)
local ls = Instance.new("Folder")
ls.Name = "leaderstats"
local m = Instance.new("IntValue",ls)
m.Name = "Chickens"
ls.Parent = plr

local cash = Instance.new("IntValue",ls)
cash.Name = "Cash"
end)

@Piglet，谢谢你，我有点理解，这是你的意思吗？

local newChicken = game.ServerStorage:FindFirstChild("ChickenOnePart")

local TopLeftCorner = Vector3.new(-187.64, 20.679, 106.2)
local BottomRightCorner = Vector3.new(201.12, 20.679, -241.45)
local numberOfChickens = 100
local counter = 0

local singleTonRandom = Random.new(tick())

local function GetRandom(Min,Max)
return singleTonRandom:NextNumber(Min,Max)
end

for counter = 1, numberOfChickens do
local chicken = newChicken:Clone()
chicken.Anchored = true
chicken.Parent = game.Workspace
chicken.Name = "Chicken"
chicken.Position = Vector3.new(
    GetRandom(TopLeftCorner.X,BottomRightCorner.X),
    4,
    GetRandom(TopLeftCorner.Z,BottomRightCorner.Z)
)
counter = counter + 1
end

function AddChicken(num)
for count = 10, num do
local chicken = newChicken:Clone()
chicken.Anchored = true
chicken.Parent = game.Workspace
chicken.Name = "Chicken"
chicken.Position = Vector3.new(
  GetRandom(TopLeftCorner.X,BottomRightCorner.X),
  4,
  GetRandom(TopLeftCorner.Z,BottomRightCorner.Z)
)
end        
end
AddChicken(90)

很抱歉，我只是在学习这一切

Answer 1

基本上，只需将while循环放在自己的函数中，然后在鸡的数量低于某个阈值时调用该函数，就像调用GetRandom将鸡放在适当的位置一样：

function GenerateChickens()
    while counter < numberOfChickens  do
        local chicken = newChicken:Clone()
        chicken.Anchored = true
        chicken.Parent = game.Workspace
        chicken.Name = "Chicken"
        chicken.Position = Vector3.new(
            GetRandom(TopLeftCorner.X,BottomRightCorner.X),
            4,
            GetRandom(TopLeftCorner.Z,BottomRightCorner.Z)
        )
        counter = counter + 1
    end
end

我不知道您如何获得当前的鸡肉数量，但这应该是一个很好的开始。

Answer 2

由于这样的循环非常常见，因此有一种比以下形式更短的形式：

local counter = 0
while counter < numberOfChickens do
  -- ...
  counter = counter + 1
end

这可以使用数字for循环来编写

for counter = 1, numberOfChickens do
  -- ...
end

当只剩下10只鸡的时候，再加100只鸡，就像你建议的那样，你会得到110只鸡。所以如果你想在地图上有100只鸡，你应该加90。

要做到这一点，您应该检查鸡肉计数，每当鸡被移走。一旦你的条件为真，你就应该调用一个函数来添加一定数量的鸡。

function AddChicken(num)
  for count = 1, num do
    local chicken = newChicken:Clone()
    chicken.Anchored = true
    chicken.Parent = game.Workspace
    chicken.Name = "Chicken"
    chicken.Position = Vector3.new(
      GetRandom(TopLeftCorner.X,BottomRightCorner.X),
      4,
      GetRandom(TopLeftCorner.Z,BottomRightCorner.Z)
    )
  end        
end

只需确保函数在newChicken的作用域内