问题:在处理异常之后，OpenScript没有转到下一次迭代

Question

我已经构建了我自己的错误处理OpenScript osing标准Java

try{
}

catch () {
}

一切都正常工作，它正确地处理异常。但问题是，之后的脚本不会转到下一次迭代，而只是调用public void finish() throws Exception {}

在成功处理异常后，如何让脚本转到下一次迭代？

Answer 1

好了，我找到解决方案了。情况是，如果OpenScript生成自己的异常(例如，找不到表单)，那么即使您使用标准Java语法捕获它，这种执行处理看起来也是有效的，但脚本不会进入下一次迭代。

因此，解决方案如下：(实际在文档中进行了描述)：

beginStep("Trying to execute code, which may go wrong", 0);

// Setting error recovery to warning, so the script will not halt       
setErrorRecovery(FormsErrorRecovery.ERR_FORMS_FT_ERROR, ErrorRecoveryAction.Warn);
        
/*
Some code, which can generate error (e.g. form is not found) needs to go here
*/

// setting error recovery back to Fail, so the script will halt at unexpected error
setErrorRecovery(FormsErrorRecovery.ERR_FORMS_FT_ERROR, ErrorRecoveryAction.Fail);
        
endStep();

// The hasLastError variable is automatically set to true if there was an error in the previous beginStep() --- endStep() block.

if(!hasLastError()){

/* code goes here to be executed if there was no error */

}

else {
 /* code goes here to execute if there was an error */
}