flutter upload doc，docx file to api laravel

Question

我感到厌烦的是，我使用file_picker选择select，然后返回如下代码。

问题是当我打印出的cv:是空的。或者有没有其他上传文件到api的方法？

//这里有函数抖动

    String cvs;
  Future getFile() async{
    var tempFile = await FilePicker.getFile(type: FileType.custom, allowedExtensions: ['doc', 'docx']);
    String fileString = jsonEncode(tempFile);

    setState(() {
      cvs = fileString;
      print(cvs);
    });
  }

//这是我的数据json代码

var data = {
  'firstName': firstNameController.text,
  'lastName': lastNameController.text,
  'gender': genderController.text,
  'experience': experienceController.text,
  'field_id': _mySelection,
  'description_filed': descriptionFiledController.text,
  'cv_type': cvTypeController.text,
  'cv': cvs
};

//后端laravel代码将信息存储在数据库和google驱动if文件中`

public function storeApi(Request $req){



        $post = new Post;
        //To associate a user with a post,
        $field = Field::all();
        $cvs = new Cv;


        $validator = Validator::make($req->all(), [
             'firstName' => 'required|max:255',
             'lastName' => 'required|max:255',
             'gender' => 'required|max:255',
             'experience' => 'required|max:255',
             'cv' => 'required|max:100000|mimes:doc,docx',

        ]);
        if($validator->fails()){
      
        return redirect('/user/create_cv')
        ->withErrors($validator)
        ->withInput();
    }
    else{
        $post->user()->associate(Auth::user());
        $post->firstName=$req->firstName;
        $post->lastName=$req->lastName;
        $post->gender=$req->gender;

        $post->field_id=$req->field_id;
       
        $post->experience=$req->experience;
        
        $post->description_filed=$req->description_filed;
        $post->cv_type=$req->cv_type;

        if($req->hasFile('cv')){


                $cvs->user()->associate(Auth::user());
                
                $cvs->cv = $req->file('cv')->store('google_folder_link', 'google');

                
                $cvs->url =  Storage::disk('google')->url($cvs->cv);
                $cvs->save();


        }


        $post->save();
    }
    return response()->json([
        'success' => "true",
        'message' => 'Post successfully',
        'post'    => $post,
        'cv'    => $cvs
        ]); 

    }`

Answer 1

您可以按如下方式获取所选的文件

File file = await FilePicker.getFile();

获得文件后，可以使用http包通过multipart request上传文件

_asyncFileUpload(File file) async {
    //create multipart request for POST or PATCH method
    var request = http.MultipartRequest("POST", Uri.parse("<request_url>"));
    // add additional fields
    // request.fields["field1"] = value1;
    
    // create multipart using filepath, string or bytes
    var fileToUpload = await http.MultipartFile.fromPath("file_field", file.path);
    //add multipart to request
    request.files.add(fileToUpload);
    var response = await request.send();

    //Get the response from the server
    var responseData = await response.stream.toBytes();
    var responseString = String.fromCharCodes(responseData);
    print(responseString);
}

一旦你得到了一个多部分的文件，你就可以很容易地在PHP中读取它。