我想要在黑白图像中反转颜色,然后用以下代码更改透明背景:
imgg = Image.open('HSPl4_E5_LP8.png')
data = np.array(imgg)
converted = np.where(data == 255, 0, 255)
imgg = Image.fromarray(converted.astype('uint8'))
imgg.save('new HSPl4_E5_LP8.png')和
from PIL import Image
img = Image.open('new HSPl4_E5_LP8.png')
img = img.convert("RGBA")
datas = img.getdata()
newData = []
for item in datas:
if item[0] == 255 and item[1] == 255 and item[2] == 255:
newData.append((255, 255, 255, 0))#0 és la alfa de rgba i significa 0 opacity.
else:
newData.append(item)
img.putdata(newData)
img.save("HSPl4_E5_LP8 transparent.png", "PNG")然后,我想在文件夹中的几个图像中迭代这一点。然后,我想将新图像与更改保存在另一个文件夹中。但我找不到一种方法来让它工作。
发布于 2020-09-25 17:36:18
我不确定我是否正确理解了你的问题,但我认为你可以这样做。首先,将两个操作捆绑到一个函数中:
from PIL import Image
def imageTransform(imgfile,destfolder):
img = Image.open(imgfile)
data = np.array(img)
converted = np.where(data == 255, 0, 255)
img = Image.fromarray(converted.astype('uint8'))
img = img.convert("RGBA")
datas = img.getdata()
newData = []
for item in datas:
if item[0] == 255 and item[1] == 255 and item[2] == 255:
newData.append((255, 255, 255, 0))
else:
newData.append(item)
img.putdata(newData)
img.save(destfolder+"/"+imgfile, "PNG")此函数将打开图像,应用您提到的更改,然后将其保存在指定的路径中。然后,您可以使用以下代码自动执行此过程:
import os
originalfolder = "folderpath" #place your folder path as string
destfolder = "folderpath" #place your destination path as string
directory = os.fsencode(originalfolder)
for file in os.listdir(directory):
filename = os.fsdecode(file)
imageTransform(file, destfolder)"originalfolder“是你的原始图片所在的文件夹。格式应类似于"C:/Users/yourfolder"
"desfolder“是存储新图像的文件夹。格式应类似于"C:/Users/yournewfolder"
发布于 2020-09-25 17:30:18
您可以使用pathlib来实现这一点,假设apply_algo是一个函数,该函数接受输入图像的路径对象,并返回转换后的PIL.Image对象。
from pathlib import Path
def process_files(source: str, dstn: str):
dstn = Path(dstn)
source = Path(source)
# check if input strings are directories or not.
if not (source.is_dir() and dstn.is_dir()):
raise Exception("Source and Dstn must be directories")
# use rglob if you want to pick files from subdirectories as well
for path in source.glob("*"):
if path.is_file():
output_img = apply_algo(path)
output_img.save(dstn / path.name(), "PNG")https://stackoverflow.com/questions/64061210
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