Python等效于提供400响应的Curl

Question

正在尝试将shell curl重写为包含请求模块的python脚本...

我的shell脚本：

#!/bin/bash

ip=$1
url=https://xxx.xx.xx.com
secret=xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
expand=computerStatus


curl --silent -X POST "$url/api/computers/search?expand=$expand" -H "Content-Type: application/json" -H "api-secret-key: $secret" -H "api-version: v1" -d '{"maxItems": 10,"searchCriteria": [{"fieldName": "hostName","stringTest": "equal", "stringValue": "'"$ip"'"}]}' -k > $file

上面的代码在bash中运行良好。

我正在尝试转换为类似的python等效项。

我尝试过的

import json
import requests
import sys

ip = sys.argv[1]

sys_info = []

url=https://xxx.xx.xx.com
secret=xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
expand=computerStatus

headers = {
    'Content-Type': 'application/json',
    'api-secret-key': secret,
    'api-version': 'v1',
}

params = (
    ('expand', 'expand'),
)

data = '{"maxItems": 10,"searchCriteria": [{"fieldName": "hostName","stringTest": "equal", "stringValue": ip}]}'

response = requests.post('https://url/api/computers/search?expand=expand', headers=headers, params=params, data=data)

print(response)

<Response [400]>

我收到了400个响应..不确定我在语法中缺失了什么……

Answer 1

数据需要是一个字典，试试这个：

data = {
    "maxItems": 10, 
    "searchCriteria": [{"fieldName": "hostName","stringTest": "equal", "stringValue": ip}]
    }

还可以将params转换为字典：

 params = {"expand" : expand}

在发帖时：

response = requests.post(f'https://{url}/api/computers/search', headers=headers, params=params, data=data)

### or alternatively you can

response = requests.post(f'https://{url}/api/computers/search?expand={expand}', headers=headers, data=data)