python TicTacToe while

Question

有一款TicTacToe游戏已经快要完成了。我只有while循环有问题。我不知道为什么我得不到"X赢“或"O赢”，只能得到“平局”。感谢您的帮助！

我不知道我还应该写什么，但有一句话：“看起来你的帖子主要是代码；请添加更多细节。”消息，所以我写了这篇文章。

x_o = [" ", " ", " ", " ", " ", " ", " ", " ", " "]

x_wins = {'row1_X': "X" == x_o[0] and "X" == x_o[1] and "X" == x_o[2],
          'row2_X': "X" == x_o[3] and "X" == x_o[4] and "X" == x_o[5],
          'row3_X': "X" == x_o[6] and "X" == x_o[7] and "X" == x_o[8],
          'col1_X': "X" == x_o[0] and "X" == x_o[3] and "X" == x_o[6],
          'col2_X': "X" == x_o[1] and "X" == x_o[4] and "X" == x_o[7],
          'col3_X': "X" == x_o[2] and "X" == x_o[5] and "X" == x_o[8],
          'slant1_X': "X" == x_o[0] and "X" == x_o[4] and "X" == x_o[8],
          'slant2_X': "X" == x_o[2] and "X" == x_o[4] and "X" == x_o[6]
          }

o_wins = {'row1_O': "O" == x_o[0] and "O" == x_o[1] and "O" == x_o[2],
          'row2_O': "O" == x_o[3] and "O" == x_o[4] and "O" == x_o[5],
          'row3_O': "O" == x_o[6] and "O" == x_o[7] and "O" == x_o[8],
          'col1_O': "O" == x_o[0] and "O" == x_o[3] and "O" == x_o[6],
          'col2_O': "O" == x_o[1] and "O" == x_o[4] and "O" == x_o[7],
          'col3_O': "O" == x_o[2] and "O" == x_o[5] and "O" == x_o[8],
          'slant1_O': "O" == x_o[0] and "O" == x_o[4] and "O" == x_o[8],
          'slant2_O': "O" == x_o[2] and "O" == x_o[4] and "O" == x_o[6]
          }

print("---------")
print("|", " ", " ", " ", "|")
print("|", " ", " ", " ", "|")
print("|", " ", " ", " ", "|")
print("---------")

coordinates = [['1', '3'], ['2', '3'], ['3', '3'], ['1', '2'], ['2', '2'], ['3', '2'], ['1', '1'], ['2', '1'],
               ['3', '1']]

count = 0

empty_places = coordinates

while True not in x_wins.values() and True not in o_wins.values() and x_o.count("X") + x_o.count("O") != 9:
    move = input("Enter the coordinates: ").split(" ")
    if move in empty_places:
        ind = coordinates.index(move)
        empty_places[ind] = [" ", " "]
        if count % 2 == 0:
            x_o[ind] = "X"
            count += 1
        else:
            x_o[ind] = "O"
            count += 1
        print("----------")
        print("|", x_o[0], x_o[1], x_o[2], "|")
        print("|", x_o[3], x_o[4], x_o[5], "|")
        print("|", x_o[6], x_o[7], x_o[8], "|")
        print("----------")
    elif move not in empty_places and move in coordinates:
        print("This cell is occupied! Choose another one!")
    elif not move[0].isdigit() and not move[1].isdigit():
        print("You should enter numbers!")
    elif move not in empty_places and int(move[0]) > 3 or int(move[1]) > 3:
        print("Coordinates should be from 1 to 3!")

if True in x_wins.values():
    print("X wins")
elif True in o_wins.values():
    print("O wins")
elif True not in x_wins.values() and True not in o_wins.values():
    print("Draw")

Answer 1

在程序开始时，您只定义了一次x_wins和o_wins，所以在整个程序运行过程中，它们都会保持初始值，也就是说，完全用False填充。要解决这个问题，应该将x_wins和o_wins放入返回字典的函数中--这样，无论何时调用x_wins()和o_wins()，它都会重新计算字典，并正确地确定其中一个是否成功。

def x_wins():
    return {'row1_X': "X" == x_o[0] and "X" == x_o[1] and "X" == x_o[2],
            'row2_X': "X" == x_o[3] and "X" == x_o[4] and "X" == x_o[5],
            'row3_X': "X" == x_o[6] and "X" == x_o[7] and "X" == x_o[8],
            'col1_X': "X" == x_o[0] and "X" == x_o[3] and "X" == x_o[6],
            'col2_X': "X" == x_o[1] and "X" == x_o[4] and "X" == x_o[7],
            'col3_X': "X" == x_o[2] and "X" == x_o[5] and "X" == x_o[8],
            'slant1_X': "X" == x_o[0] and "X" == x_o[4] and "X" == x_o[8],
            'slant2_X': "X" == x_o[2] and "X" == x_o[4] and "X" == x_o[6]
           }