当有范围条件时，如何使用for循环创建新的子文件夹？

Question

现在我试着每天用python自动化创建新的目录文件夹，我需要根据我的列表创建新的Fix子文件夹。如下所示：

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这是我的脚本：

import os
from datetime import date
today = date.today()
d1 = today.strftime("%d-%m-%Y")
#Ie Source Path
ie = ["G:/01-FIN & ACC-Confidential/Inbound/IE-Direct/",
"G:/02-BDSM (ห้ามย้ายเด็ดขาด)-Confidential/Inbound/IE-Direct/",
"G:/03-BSC-Confidential/Inbound/IE-Direct/",
"G:/04-CLD-Confidential/Inbound/IE-Direct/",
"G:/05-COMPLIANCE-Confidential/Inbound/IE-Direct/",
"G:/06-CRD-Confidential/Inbound/IE-Direct/",

# define the access rights
access_rights = 0o755

team = ["ACCOUNTING","BDSM","BSC","CLD","COMPLIANCE","CRD","HR","IT","MGT","MKT","OPS","COPORATE SALES","TELESALES","PASSAPORN","FRAUD","LEGAL","INS","BIQM",]

for i,j in ie+team:
    os.mkdir(i+str(d1)+"/"+j)

请告诉我如何在已经用当前程序创建的文件夹中创建子目录。

Answer 1

我试过你的代码，但它显示的值太多，无法解压，然后我修改了你的代码，创建了6个目录，然后在这6个目录中再次创建了3个子目录。

from datetime import date
today = date.today()
d1 = today.strftime("%d-%m-%Y")
#Ie Source Path
ie = ["D:/t/",
"D:/t/",
"D:/t/",
"D:/t/",
"D:/t/",
"D:/t/"]

# define the access rights
access_rights = "0o755"

team = ["ACCOUNTING","BM","BSC","CLD","COMPLIANCE","CRD"]//actual 6 directories 
new_subs=["1","2","3"] //names of 3 subdirectories

os.mkdir(ie[0]+str(d1))//main directory named as today's date

for i in range(0,6):
    os.mkdir(ie[i]+str(d1)+"/"+team[i])
    for j in range(len(new_subs)):
        os.mkdir(ie[i]+str(d1)+"/"+team[i]+"/"+new_subs[j])

如果他们对代码有任何疑问，请给出评论