如何解决Python smtpd的问题？

Question

我想使用Python创建一个小型SMTP服务器进行测试，所以我尝试了服务器示例代码

https://pymotw.com/2/smtpd/

import smtpd
import asyncore

class CustomSMTPServer(smtpd.SMTPServer):

def process_message(self, peer, mailfrom, rcpttos, data):
    print 'Receiving message from:', peer
    print 'Message addressed from:', mailfrom
    print 'Message addressed to  :', rcpttos
    print 'Message length        :', len(data)
    return

server = CustomSMTPServer(('127.0.0.1', 1025), None)

asyncore.loop()

以及同一页面上的示例客户端代码：

import smtplib
import email.utils
from email.mime.text import MIMEText

# Create the message
msg = MIMEText('This is the body of the message.')
msg['To'] = email.utils.formataddr(('Recipient', 'recipient@example.com'))
msg['From'] = email.utils.formataddr(('Author', 'author@example.com'))
msg['Subject'] = 'Simple test message'

server = smtplib.SMTP('127.0.0.1', 1025)
server.set_debuglevel(True) # show communication with the server
try:
    server.sendmail('author@example.com', ['recipient@example.com'], msg.as_string())
finally:
    server.quit()

然而，当我尝试运行客户端时，我在服务器端得到了以下结果：

error: uncaptured python exception, closing channel <smtpd.SMTPChannel connected 127.0.0.1:38634 at 0x7fe28a901490> (<class 'TypeError'>:process_message() got an unexpected keyword argument 'mail_options' [/root/Python-3.8.1/Lib/asyncore.py|read|83] [/root/Python-3.8.1/Lib/asyncore.py|handle_read_event|420] [/root/Python-3.8.1/Lib/asynchat.py|handle_read|171] [/root/Python-3.8.1/Lib/smtpd.py|found_terminator|386])
^CTraceback (most recent call last):
  File "./mysmtpd.py", line 18, in <module>
asyncore.loop()
  File "/root/Python-3.8.1/Lib/asyncore.py", line 203, in loop
poll_fun(timeout, map)
  File "/root/Python-3.8.1/Lib/asyncore.py", line 144, in poll
r, w, e = select.select(r, w, e, timeout)
KeyboardInterrupt

然后我找到了这个问题页面：

https://bugs.python.org/issue35837

我认为这就是我一直遇到的问题。

这个问题还没有解决，所以我想知道，在此期间，是否可以在示例客户端代码中修改一些东西，以绕过该问题中描述的问题？

谢谢，吉姆

Answer 1

在process_message()函数中添加一个mail_options=None。

Answer 2

仅供参考，对rcpt_options参数执行相同的操作。

参考：https://docs.python.org/3/library/smtpd.html?highlight=process_message#smtpd.SMTPServer.process_message

Answer 3

错误似乎出现在def process_message(self, peer, mailfrom, rcpttos, data):行中。您可以将其替换为def process_message(self, peer, mailfrom, rcpttos, data,**my_krargs):