我需要在不使用dateFromString运算符中的format字段的情况下将日期值解析为特定格式。
现状:在MongoDB4.0中,如果我使用下面的代码格式化dateString,它会给出我提到的输出。
parsedDate: {
$dateFromString: {
dateString: "$dateS",
format: format: "%Y-%m-%dT%H"
}
}
Output: "parsedDate": ISODate("2020-01-16T08:00:00Z")我不能在3.6中使用格式字段,因为它不被支持。如何在3.6中将日期转换为format: "%Y-%m-%dT%H"?
发布于 2020-04-13 00:56:44
如果我得到了正确的需求,请尝试使用以下查询:$dateFromParts
输入:
[
{
"date": ISODate("2020-01-16T08:54:17.604Z")
}
]查询:
db.collection.aggregate([
{
$project: {
outputDate: {
$dateFromParts: {
"year": {
$year: "$date"
},
"month": {
$month: "$date"
},
"day": {
$dayOfMonth: "$date"
},
"hour": {
$hour: "$date"
}
}
}
}
}
]);O/P:
[
{
"_id": ObjectId("5a934e000102030405000000"),
"outputDate": ISODate("2020-01-16T08:00:00Z")
}
]发布于 2020-04-13 02:06:52
我认为下面的查询将解决您的问题,因为MongoDB 3.6支持dateFromString
输入:
[
{
"dateS": "2020-01-16T08"
}
]查询:
db.collection.aggregate([
{
"$project": {
"year": {"$substr": ["$dateS",0,4]},
"month": {"$substr": ["$dateS",5,2]},
"day": {"$substr": ["$dateS",8,2]},
"hour": {"$substr": ["$dateS",11,2]}
}
},
{
$addFields: {
"isoString": {
"$concat": ["$year","-","$month","-","$day","T","$hour",":00:00Z"]
}
}
},
{
$addFields: {
"newDate": {
$dateFromString: {"dateString": "$isoString"}
}
}
}
])输出:
[
{
"_id": ObjectId("5a934e000102030405000000"),
"day": "16",
"hour": "08",
"isoString": "2020-01-16T08:00:00Z",
"month": "01",
"newDate": ISODate("2020-01-16T08:00:00Z"),
"year": "2020"
}
]发布于 2020-04-13 03:07:06
这对我很有效:我使用了@ambienBeing和@techstack的组合解决方案。谢谢
"parsedDate": {
"$dateFromParts": {
"year": {
"$year": {
$dateFromString: {
dateString: {
"$concat": [
"$_id.dateHour",
":00:00Z"
]
}
}
}
},
"month": {
"$month": {
$dateFromString: {
dateString: {
"$concat": [
"$_id.dateHour",
":00:00Z"
]
}
}
}
},
"day": {
"$dayOfMonth": {
$dateFromString: {
dateString: {
"$concat": [
"$_id.dateHour",
":00:00Z"
]
}
}
}
},
"hour": {
"$hour": {
$dateFromString: {
dateString: {
"$concat": [
"$_id.dateHour",
":00:00Z"
]
}
}
}
}
}
},https://stackoverflow.com/questions/61174221
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