我的If-Else条件代码接收用户输入并按“热”或“冷”对数据进行分类，这是怎么回事？

Question

HighTemp1= input()
print(‘Temperature 1:’ +  HighTemp1)
LowTemp2= input()
print(‘Temperature 2:’ + LowTemp2)
if (HighTemp1>80):
   print( ‘The high temperature was Hot’)
elif(HighTemp1> 40 and <80):
   print(‘The high temperature was Average’)
else:
   print(‘The high temperature was Cold’)

if (LowTemp2>80):
   print( ‘The low temperature was Hot’)
elif(LowTemp2> 40 and <80):
   print(‘The low temperature was Average’)
else:
   print(‘The low temperature was Cold’)

因此，我假设确定一天内两个用户输入温度的类别，并以以下方式输出：

Temp        Category
>80         Hot
40 to 80    Average
<40         Cold

Example#1:温度1: 81温度2: 37高温为热低温为冷

我在这段代码中遇到了太多的错误，我不确定哪里出了问题。代码不会在IDLE中运行，因为当我逐行运行它时(因为我得到了一个多语句错误)，要么是类型错误"cannot use > operator with The int and string“，要么是语法错误。我有什么不理解的地方使我的代码无法运行？

Answer 1

我假设您使用的是Python3。您的代码中有许多错误

HighTemp1= int(input())  #to take int input, you need to parse it to int. as input() directly reads a string
print("Temperature 1:" +  str(HighTemp1)) #print in python3 assumes string in "" 
LowTemp2= int(input())
print("Temperature 2:" + str(LowTemp2)) #int can't be directly concatenated to string. You need to parse it to string using str() to concat it with string
if (HighTemp1>80):
    print( "The high temperature was Hot")
elif(HighTemp1> 40 and  <80):
    print("The high temperature was Average")
else:
    print("The high temperature was Cold")

if (LowTemp2>80):
    print( "The low temperature was Hot")
elif(LowTemp2> 40 and <80):
    print("The low temperature was Average")
else:
    print("The low temperature was Cold")

Answer 2

首先，input()返回一个字符串。为了进行比较，您需要将其转换为int类型。第二，注意你的“语录”。在字符串中用作引号的字符不是简单的ASCII。我把它们都换了。第三，你的比较是有缺陷的。我重做了“高”的部分，只修复了“低”的部分。你可以看到不同之处。此外，input()方法将字符串作为输入参数输出给用户，这样他/她就知道要输入什么了。这可能是一件好事。

HighTemp1 = int(input('High: ').strip())
print('Temperature 1: %d' %  HighTemp1)
LowTemp2= int(input('Low: ').strip())
print('Temperature 2: %d' % LowTemp2)
if HighTemp1 > 80:
   print('The high temperature was Hot')
# elif 40 < HighTemp1 <= 80: # simplifies to next line
elif HighTemp1 > 40:
   print('The high temperature was Average')
else:
   print('The high temperature was Cold')

if (LowTemp2 > 80):  # parens not required here
   print('The low temperature was Hot')
elif(LowTemp2 > 40):  # and LowTemp2<=80):
#                     # the above is redundant
# note that your original "and LowTemp2<80" introduced a bug for value 80
   print('The low temperature was Average')
else:
   print('The low temperature was Cold')