React Typescript -在路由中传递类型时如何将类型添加到location.state

Question

当我传递react-router props发送到Route中的一个组件时，我收到一个错误，因为我有一个特定的状态，我传递了这个组件，但这个错误显示在我的Route中。

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以下是路由代码：

<Route
    exact
    path='/flipltimeline'
    render={props => <FliplTimeline {...props} />

在另一个组件中，我在下面调用它

props.history.push(`/flipltimeline`, {
      Approval: singleFliplApprovals,
      InvestigationID,
      Unit: unit,
      Cost: cost
    });

以下是组件的代码。我最终得到了Typescript来编译它，但我必须合并LocationState和TimelineState才能让它工作。但是现在，当我向FliplTimeline组件发送道具时，Typescript会抛出上面的屏幕截图。有谁知道怎么解决这个问题吗？

history.tsx

import { createBrowserHistory } from 'history';

let baseNameProd = '';

if (process.env.NODE_ENV !== 'production') {
  console.log('Looks like we are in development mode!');
  baseNameProd = '';
} else {
  baseNameProd = '/flipl';
}

const customHistory = createBrowserHistory({
  basename: baseNameProd
});

export default customHistory;

FliplTimeline.tsx

import * as React from 'react';
import { History, LocationState } from 'history';

interface FliplTimelineLocationState {
  Approval: any;
  InvestigationID: number;
  Unit: string;
  Cost: number;
}

interface TimelineState{
  state: FliplTimelineLocationState;
}

interface Props {
  history: History;
  location: LocationState & TimelineState;
}

function FliplTimeline(props: Props) {
  return (
    <ModuleTemplate title='Status Timeline' subtitle=''>
      <FliplTimelineJumbotron className='bg-primary-darker shadow-4 line-height-serif-4'>
        <div className='grid-row'>
          <div className='grid-col-4'>
            <span
              className='font-mono-2xl text-white'
              style={{
                verticalAlign: 'middle'
              }}
            >
              FLIPL{' '}
            </span>
            <span
              className='font-mono-xl text-gold'
              style={{
                verticalAlign: 'middle'
              }}
            >
              {props.location.state.InvestigationID}
            </span>

更新:添加了我的history.tsx文件，我在其中为React-Router创建了自己的历史记录。在导入语句中也添加了。

更新:尝试将我的FliplTimeline组件更改为具有此接口

import { RouteComponentProps } from 'react-router-dom'

function FliplTimeline(props: RouteComponentProps ) {

我得到两个错误。第一个是这个，另一个是说道具的形状是错误的。想法？

​

更新:我终于能够为我的组件获得正确的props声明。

import { RouteComponentProps } from 'react-router-dom';

interface FliplTimelineLocationState {
  Approval: any;
  InvestigationID: number;
  Unit: string;
  Cost: number;
}

function FliplTimeline(
  props: RouteComponentProps<{}, any, FliplTimelineLocationState | any>
)

Answer 1

我能让它工作起来。

import { RouteComponentProps } from 'react-router-dom';

interface FliplTimelineLocationState {
  Approval: any;
  InvestigationID: number;
  Unit: string;
  Cost: number;
}

function FliplTimeline(
  props: RouteComponentProps<{}, any, FliplTimelineLocationState | any>
)

Answer 2

使用RouteComponentProps并为其泛型提供适当的类型。本文涵盖了相当多的内容：How to Use React Router in Typescript。

将React Router与TypeScript一起使用几乎需要填充React Router所具有的泛型。否则，没有足够的上下文来确定所有内容的类型。与我下面的示例进行比较。我使用useHistory并用我想要提供的类型填充它。这可能是您的FliplTimelineLocationState，这样history的state属性就可以确定为FliplTimelineLocationState类型。

import React, {MouseEventHandler} from "react";
import {Route, RouteComponentProps, StaticContext, useHistory} from "react-router";
import {BrowserRouter, Link} from "react-router-dom";

interface IMyScreenRouteParams {
    foo: string;
}

// You don't have to extend, you could just use StaticContext
interface IMyStaticContext extends StaticContext {
    bar: string;
}

interface IHistory {
    fizz: string;
}

const Nav = () => {
    const history = useHistory<IHistory>();

    const clickHanlder: MouseEventHandler = () => {
        history.push("/my-screen", {
            fizz: "you said fizz"
        });
    };

    return (
        <nav>
            <ul>
                <li><Link to="/">Home</Link></li>
                <li><Link to="/my-screen">My Screen</Link></li>
                <li><button onClick={clickHanlder}>My Screen with state</button></li>
                <li><Link to="/my-screen?q=hello">My Screen with query</Link></li>
                <li><Link to="/my-screen/bob">My Screen using match</Link></li>
            </ul>
            <div>
                <button onClick={() => history.goBack()}>Back</button>
                <button onClick={() => history.push("/")}>Home</button>
                <button onClick={() => history.goForward()}>Forward</button>
            </div>
        </nav>
    );
};

const MyScreen = ({
    location,
    match,
    history,
    staticContext
}: RouteComponentProps<IMyScreenRouteParams, IMyStaticContext, IHistory>) => (
    <div>
        <section>
            <h2>Location</h2>
            <p><code>location</code> has <code>IHistory</code> props.</p>
            <pre><code>{JSON.stringify(location, null, 4)}</code></pre>
        </section>
        <section>
            <h2>Match</h2>
            <p><code>match</code> has <code>IMyScreenRouteParams</code> props.</p>
            <pre><code>{JSON.stringify(match, null, 4)}</code></pre>
        </section>
        <section>
            <h2>History</h2>
            <p><code>history</code> has <code>IHistory</code> props.</p>
            <pre><code>{JSON.stringify(history, null, 4)}</code></pre>
        </section>
        <section>
            <h2>Static Context</h2>
            <p><code>staticContext</code> has <code>IMyStaticContext</code> props or whatever static context your router has.</p>
            <p>This is for a <a href="https://reacttraining.com/react-router/web/api/StaticRouter/context-object"><code>&lt;StaticRouter/&gt;</code></a>.</p>
            <pre><code>{JSON.stringify(staticContext, null, 4)}</code></pre>
        </section>
    </div>
);

const Router = () => (
    <BrowserRouter>
        <div
            style={{
                display: "flex",
                flexDirection: "row"
            }}
        >
            <Nav />
            <main>
                <Route exact path="/" component={() => (<div>Click something in the <code>&lt;nav/&gt;</code></div>)} />
                <Route exact path="/my-screen" component={MyScreen} />
                <Route exact path="/my-screen/:id" component={MyScreen} />
            </main>
        </div>
    </BrowserRouter>
);

export default Router;